第一种方法: import collectionsd = collections.OrderedDict([( ‘ a ‘ ,1),( ‘ b ‘ ,2),( ‘ c ‘ ,3 )]) ‘‘‘ 或者把上面的那一行改成: d = collections.OrderedDict() d[‘a‘] = 1 d[‘b‘] = 2 d[‘c‘] = 3 ‘
          第一种方法:
import collections d = collections.OrderedDict([(‘a‘,1),(‘b‘,2),(‘c‘,3)]) ‘‘‘ 或者把上面的那一行改成: d = collections.OrderedDict() d[‘a‘] = 1 d[‘b‘] = 2 d[‘c‘] = 3 ‘‘‘ for k,v in d.items(): print(k,v) 输出结果: a 1 b 2 c 3
第二种方法:
from collections import OrderedDict d = OrderedDict([(‘a‘, 1), (‘b‘, 2), (‘c‘, 3)]) for k,v in d.items(): print(k,v) 输出结果: a 1 b 2 c 3
第三种方法:
d = {‘a‘:1, ‘b‘:2, ‘c‘:3}
e = [‘a‘, ‘b‘, ‘c‘]
for i in range(3):
    print( str(e[i]) + " " + str(d[e[i]]) )
    # 这里的键值是 int 型数字,需要 str() 转一下
输出结果:
        a 1
        b 2
        c 3 
        
             