我试图基于时间序列数据的滑动窗口提取功能. 在 Scala中,似乎有一个基于 this post和 the documentation的滑动功能 import org.apache.spark.mllib.rdd.RDDFunctions._sc.parallelize(1 to 100, 10) .sliding(3) .map(cur
          在 Scala中,似乎有一个基于 this post和 the documentation的滑动功能
import org.apache.spark.mllib.rdd.RDDFunctions._ sc.parallelize(1 to 100, 10) .sliding(3) .map(curSlice => (curSlice.sum / curSlice.size)) .collect()
我的问题是PySpark中有类似的功能吗?或者,如果没有这样的功能,我们如何实现类似的滑动窗口转换呢?
据我所知,滑动功能不能从Python获得,SlidingRDD是私有类,不能在MLlib外部访问.如果你在现有的RDD上使用滑动,你可以像这样创建穷人滑动:
def sliding(rdd, n):
    assert n > 0
    def gen_window(xi, n):
        x, i = xi
        return [(i - offset, (i, x)) for offset in xrange(n)]
    return (
        rdd.
        zipWithIndex(). # Add index
        flatMap(lambda xi: gen_window(xi, n)). # Generate pairs with offset
        groupByKey(). # Group to create windows
        # Sort values to ensure order inside window and drop indices
        mapValues(lambda vals: [x for (i, x) in sorted(vals)]).
        sortByKey(). # Sort to makes sure we keep original order
        values(). # Get values
        filter(lambda x: len(x) == n)) # Drop beginning and end 
 或者你可以尝试这样的东西(在toolz的小帮助下)
from toolz.itertoolz import sliding_window, concat
def sliding2(rdd, n):
    assert n > 1
    def get_last_el(i, iter):
        """Return last n - 1 elements from the partition"""
        return  [(i, [x for x in iter][(-n + 1):])]
    def slide(i, iter):
        """Prepend previous items and return sliding window"""
        return sliding_window(n, concat([last_items.value[i - 1], iter]))
    def clean_last_items(last_items):
        """Adjust for empty or to small partitions"""
        clean = {-1: [None] * (n - 1)}
        for i in range(rdd.getNumPartitions()):
            clean[i] = (clean[i - 1] + list(last_items[i]))[(-n + 1):]
        return {k: tuple(v) for k, v in clean.items()}
    last_items = sc.broadcast(clean_last_items(
        rdd.mapPartitionsWithIndex(get_last_el).collectAsMap()))
    return rdd.mapPartitionsWithIndex(slide)
        
             