MySQL按日期分组并统计截止当前时间的总数
建表语句
SET NAMES utf8mb4;
SET FOREIGN_KEY_CHECKS = 0;
-- ----------------------------
-- Table structure for t_reg
-- ----------------------------
DROP TABLE IF EXISTS `t_reg`;
CREATE TABLE `t_reg` (
`ID` int(11) NOT NULL AUTO_INCREMENT COMMENT 'ID编号',
`REG_TIME` datetime(0) NULL DEFAULT NULL COMMENT '时间',
`REG_COUNT` int(11) NULL DEFAULT NULL COMMENT '数量',
PRIMARY KEY (`ID`) USING BTREE
) ENGINE = InnoDB AUTO_INCREMENT = 8 CHARACTER SET = utf8mb4 COLLATE = utf8mb4_general_ci ROW_FORMAT = Dynamic;
-- ----------------------------
-- Records of t_reg
-- ----------------------------
INSERT INTO `t_reg` VALUES (1, '2019-05-01 08:08:12', 1);
INSERT INTO `t_reg` VALUES (2, '2019-05-02 00:09:09', 10);
INSERT INTO `t_reg` VALUES (3, '2019-05-02 13:08:08', 2);
INSERT INTO `t_reg` VALUES (4, '2019-05-03 15:08:05', 4);
INSERT INTO `t_reg` VALUES (5, '2019-05-03 17:08:08', 6);
INSERT INTO `t_reg` VALUES (6, '2019-05-16 21:01:12', 4);
INSERT INTO `t_reg` VALUES (7, '2019-05-03 05:08:09', 11);
SET FOREIGN_KEY_CHECKS = 1;
表结构如下所示：REG_COUNT 表示当天新增的用户数
现在的需求是这样的：按每天分组，查询当天新增的用户总数和截止到当前时间新增的用户总数，结果如下:
SQL语句如下:
SELECT
reg_time,
min_total AS '小计',
@total := @total + min_total AS '总计'
FROM
( SELECT date( reg_time ) AS reg_time,
sum( reg_count ) AS min_total FROM t_reg GROUP BY date( reg_time ) ) AS temp,
( SELECT @total := 0 ) AS T1
ORDER BY
reg_time;
解释一下:SELECT @total := 0,,这句的意思是给临时变量@total设置值为0;
如此即可得出上面的结果满足需求.