快速测试创建项目与app django-admin startproject mysite django-admin startapp app1 django-admin startapp app2 mysite下的urls.py文件 from django.contrib import adminfrom django.urls import include, pathurlpatterns = [ path('admin
快速测试创建项目与app
django-admin startproject mysite
django-admin startapp app1
django-admin startapp app2
mysite下的urls.py文件
from django.contrib import admin from django.urls import include, path urlpatterns = [ path('admin/', admin.site.urls), path('app1/', include('apps.app1.urls',namespace='app1')), path('app2/', include('apps.app2.urls',namespace= 'app2')), ]
app1下的apps文件
from django.apps import AppConfig class App1Config(AppConfig): name = 'apps.app1'
app2下的apps文件
from django.apps import AppConfig class App2Config(AppConfig): name = 'apps.app2'
app1下的urls.py文件
from django.urls import path from . import views app_name = 'app1' urlpatterns = [ path('index', views.index), ]
app2下的urls.py文件
from django.urls import path from . import views app_name = 'app2' urlpatterns = [ path('index', views.index), ]
app1下的views.py文件
from django.shortcuts import render from django.shortcuts import HttpResponse def index(request): return HttpResponse('hello app1')
app2下的views.py文件
from django.shortcuts import render from django.shortcuts import HttpResponse def index(request): return HttpResponse('hello app2')
settings.py文件下的app配置:
'apps.app1.apps.App1Config', 'apps.app2.apps.App2Config'
启动
python manage.py runserver 8080
最后访问url路径
在这种设置下,在一个app访问另一个app的model
from apps.app名.models import 模型类
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持易盾网络。