英文文档: reversed(seq) Return a reverse iterator. seq must be an object which has a __reversed__() method or supports the sequence protocol (the __len__() method and the __getitem__() method with integer arguments starting at 0). 反转
英文文档:
reversed(seq)
Return a reverse iterator. seq must be an object which has a __reversed__() method or supports the sequence protocol (the __len__() method and the __getitem__() method with integer arguments starting at 0).
反转序列生成新的可迭代对象
说明:
1. 函数功能是反转一个序列对象,将其元素从后向前颠倒构建成一个新的迭代器。
>>> a = reversed(range(10)) # 传入range对象 >>> a # 类型变成迭代器 <range_iterator object at 0x035634E8> >>> list(a) [9, 8, 7, 6, 5, 4, 3, 2, 1, 0] >>> a = ['a','b','c','d'] >>> a ['a', 'b', 'c', 'd'] >>> reversed(a) # 传入列表对象 <list_reverseiterator object at 0x031874D0> >>> b = reversed(a) >>> b # 类型变成迭代器 <list_reverseiterator object at 0x037C4EB0> >>> list(b) ['d', 'c', 'b', 'a']
2. 如果参数不是一个序列对象,则其必须定义一个__reversed__方法。
# 类型Student没有定义__reversed__方法 >>> class Student: def __init__(self,name,*args): self.name = name self.scores = [] for value in args: self.scores.append(value) >>> a = Student('Bob',78,85,93,96) >>> reversed(a) # 实例不能反转 Traceback (most recent call last): File "<pyshell#37>", line 1, in <module> reversed(a) TypeError: argument to reversed() must be a sequence >>> type(a.scores) # 列表类型 <class 'list'> # 重新定义类型,并为其定义__reversed__方法 >>> class Student: def __init__(self,name,*args): self.name = name self.scores = [] for value in args: self.scores.append(value) def __reversed__(self): self.scores = reversed(self.scores) >>> a = Student('Bob',78,85,93,96) >>> a.scores # 列表类型 [78, 85, 93, 96] >>> type(a.scores) <class 'list'> >>> reversed(a) # 实例变得可以反转 >>> a.scores # 反转后类型变成迭代器 <list_reverseiterator object at 0x0342F3B0> >>> type(a.scores) <class 'list_reverseiterator'> >>> list(a.scores) [96, 93, 85, 78]
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