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无法在Swift 2.3中编译Siri扩展

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我想在我的应用程序中集成Siri / Intent扩展,目前基于 Swift 2.3.我正在使用Xcode 8 beta 6版本. 该应用程序甚至无法编译,发出错误 Type ‘IntentHandler’ does not conform to protocol ‘INSendMessageIntentH
我想在我的应用程序中集成Siri / Intent扩展,目前基于 Swift 2.3.我正在使用Xcode 8 beta 6版本.

该应用程序甚至无法编译,发出错误

Type ‘IntentHandler’ does not conform to protocol ‘INSendMessageIntentHandling’

Protocol requires function ‘handle(sendMessage:completion:)’ with type ‘(sendMessage: INSendMessageIntent, completion: (INSendMessageIntentResponse) -> Void) -> Void’

Objective-C method ‘handleWithSendMessage:completion:’ provided by method ‘handle(sendMessage:completion:)’ does not match the requirement’s selector (‘handleSendMessage:completion:’)


即使是来自Apple的示例应用程序,UnicornChat也无法使用相同的错误进行编译.我确实将SWIFT_VERSION标志更改为是,以支持Swift 2.3

示例代码:

func handle(sendMessage intent: INSendMessageIntent, completion: (INSendMessageIntentResponse) -> Void) {
        let userActivity = NSUserActivity(activityType: NSStringFromClass(INSendMessageIntent.self))
        let response = INSendMessageIntentResponse(code: .Success, userActivity: userActivity)
        completion(response)
    }

这失败并出现上述错误.

任何人都知道如何让Siri在Swift 2.3中工作?

所以,这有帮助

https://forums.developer.apple.com/message/174455#174455

我们需要使用Swift定义@objc方法签名.如下面的作品.

@objc (handleSendMessage:completion:)
func handle(sendMessage intent: INSendMessageIntent, completion: (INSendMessageIntentResponse) -> Void) {
 //..
}
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