swift – 如何覆盖Observable for Testing的清酒？

我们正在使用 Swift 2.x(最新)并想要BDD(单元测试)我们的代码.另外,我们也使用 RxSwift.我们的重写方法不会在我们的自定义测试存根中调用.我们的代码：

protocol SomethingDeliverable {
    func fetchSomething(somethingId: String, associatedList: String) -> Observable<String>
}

extension SomethingDeliverable {
    func fetchSomething(somethingId: String, associatedList: String) -> Observable<String> {
        return create { observer in
            return NopDisposable.instance
        }
    }
}

为了测试,我们有这个测试代码：

private class StubSomethingApi: SomethingDeliverable {

    var responseClosure: ((AnyObserver<String>) -> Void)?

    func fetchSomething(somethingId: String, associatedList: String) -> Observable<String> {
        return create { observer in
            if let responseClosure = self.responseClosure {
                responseClosure(observer)
            }
            return NopDisposable.instance
        }
    }
}

我们希望返回Observable< T>而不是返回Observable< String>的fetchSomething.并让StubSomethingAPI成功覆盖它以测试sakes.
我们怎么做？

这是你想要的？

protocol SomethingDeliverable {
    associatedtype Element

    func fetchSomething(somethingId: String, associatedList: String) -> Observable<Element>
}

extension SomethingDeliverable {
    func fetchSomething(somethingId: String, associatedList: String) -> Observable<Element> {
        return create { observer in
            return NopDisposable.instance
        }
    }
}

private class StubSomethingApi<T>: SomethingDeliverable {

    typealias Element = T

    var responseClosure: ((AnyObserver<T>) -> Void)?

    func fetchSomething(somethingId: String, associatedList: String) -> Observable<T> {
        return create { observer in
            if let responseClosure = self.responseClosure {
                responseClosure(observer)
            }
            return NopDisposable.instance
        }
    }
}