当将Int成员的元组分配给Int符合的(异构)协议类型的元组时,似乎只允许通过显式的逐个成员赋值来执行此赋值. protocol MyType {}extension Int: MyType {}let intPair = (1, 2)var myTypePair : (MyType, MyType
protocol MyType {} extension Int: MyType {} let intPair = (1, 2) var myTypePair : (MyType, MyType) // OK myTypePair = (intPair.0, intPair.1) // OK let intPairToMyTypePair : ((Int, Int)) -> (MyType, MyType) = { ($0.0, $0.1) } myTypePair = intPairToMyTypePair(intPair) // For all below: // "Error: cannot express tuple conversion '(Int, Int)' to '(MyType, MyType)'" myTypePair = intPair myTypePair = (intPair as! (MyType, MyType)) /* warning: forced cast from '(Int, Int)' to '(MyType, MyType)' always succeeds <-- well, not really */ if let _ = intPair as? (MyType, MyType) { } /* warning: conditional cast from '(Int, Int)' to '(MyType, MyType)' always succeeds */
特点是,对于上面的转换情况,Swift编译器警告说
warning: forced/conditional cast from
'(Int, Int)'
to'(MyType, MyType)'
always succeeds
它显然没有:
error: cannot express tuple conversion
'(Int, Int)'
to'(MyType, MyType)'
问题:这里的问题是,是否按预期不允许直接转让?如果是这样,怎么了警告信息,铸件将永远成功?
(编辑补充)
为了进一步澄清我在这里要求的特殊行为:我想知道为什么即使Swift警告我们“是”的情况总是如此,以下片段也会打印出“bar”:
let intPair = (1, 2) switch intPair { case is (MyType, MyType): print("foo") /* warning: 'is' test is always true */ case _ : print("bar") } // "bar"
数组的类似情况很简单,有解释错误,但我不知道这是否是一个有效的比较,因为元组更多是匿名结构而不是某些表兄.
let intArr = [Int](1...5) var myTypeArr : [MyType] myTypeArr = intArr /* error: cannot assign value of type '[Int]' to type '[MyType]' */ if let _ = intArr as? [MyType] { } /* error: 'MyType' is not a subtype of 'Int' */在这种情况下警告是正确的,因为intPair是(Int,Int)符合(MyType,MyType).所以演员阵容将永远成功.由于强类型检查,编译器知道此特定实例将始终成功.
为什么myTypePair = intPair错误是因为myTypePair比intPair更通用,更具体.因此类型不匹配,因此无法分配.