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swift – 来自'[NSObject:AnyObject]?’不相关的类型’NSDictionary’总是失败

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这行让userInfo = notification.userInfo为! NSDictionary我得到一个警告:来自'[NSObject:AnyObject]?’不相关的类型’NSDictionary’总是失败 我尝试使用let userInfo = notification.userInfo作为!字典 NSObj
这行让userInfo = notification.userInfo为! NSDictionary我得到一个警告:来自'[NSObject:AnyObject]?’不相关的类型’NSDictionary’总是失败

我尝试使用let userInfo = notification.userInfo作为!字典< NSObject:AnyObject>将let userInfo = notification.userInfo替换为!的NSDictionary.但我收到一个错误:预计’>’完成通用参数列表.如何修复警告.

Xcode 7.1 OS X Yosemite

这是我的代码:

func keyboardWillShow(notification: NSNotification) {

    let userInfo = notification.userInfo as! NSDictionary //warning

    let keyboardBounds = (userInfo[UIKeyboardFrameEndUserInfoKey] as! NSValue).CGRectValue()
    let duration = (userInfo[UIKeyboardAnimationDurationUserInfoKey] as! NSNumber).doubleValue
    let keyboardBoundsRect = self.view.convertRect(keyboardBounds, toView: nil)

    let keyboardInputViewFrame = self.finishView!.frame

    let deltaY = keyboardBoundsRect.size.height

    let animations: (()->Void) = {

        self.finishView?.transform = CGAffineTransformMakeTranslation(0, -deltaY)
    }

    if duration > 0 {



    } else {

        animations()
    }


}
NSNotification的userInfo属性已定义为(n可选)字典.

所以你根本不需要施放它,只需打开它.

func keyboardWillShow(notification: NSNotification) {
    if let userInfo = notification.userInfo {
        ...
    }
}

所有其余的代码应该按原样运行.

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