我正在使用 XML :: Lib XML(Ver:1.70). 我的xml输入文件如下所示: ?xml version="1.0" encoding="UTF-8"?Equipment xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" Equipments ECI
我的xml输入文件如下所示:
<?xml version="1.0" encoding="UTF-8"?>
<Equipment xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Equipments>
<ECID logicalName="SysNameAlpha" id="0"/>
<ECID logicalName="SysNameBeta" id="1"/>
</Equipments>
</Equipment>
和我的Perl脚本:
my $file = 'data.xml';
my $parser = XML::LibXML->new();
my $tree = $parser->parse_file($file);
my $root = $tree->getDocumentElement;
foreach my $camelid ($root->findnodes('Equipments')) {
my $name = $camelid->findvalue('ECID/@logicalName');
my $id = $camelid->findvalue('ECID/@id');
print $name;
print " = ";
print $id;
print ";\n";
}
我得到的输出是:
SysNameAlphaSysNameBeta = 01;
但我想要这样的输出:
SysNameAlpha = 0; SysNameBeta = 1;
我怎样才能做到这一点?
只有一个Equipments节点,因此您只能获得一个$camelid进行扫描.要进行补救,您可能会稍微改变一下,例如,迭代设备/ ECID:foreach my $camelid ( $root->findnodes('Equipments/ECID') ) {
my $name = $camelid->findvalue('@logicalName');
my $id = $camelid->findvalue('@id');
...
}
