我有两个 XML文件 tree.xml tree xi:include href="fruit.xml" xmlns:xi="http://www.w3.org/2001/XInclude" xi:fallback fruit/ /xi:fallback /xi:include/tree fruit.xml fruit .../fruit 我继承了解组文件的代码,它返回一个java对象
tree.xml
<tree> <xi:include href="fruit.xml" xmlns:xi="http://www.w3.org/2001/XInclude"> <xi:fallback> <fruit/> </xi:fallback> </xi:include> </tree>
fruit.xml
<fruit> ... </fruit>
我继承了解组文件的代码,它返回一个java对象.我现在需要将单个java对象编组回两个文件.我意识到还有其他解决方案(即使用两个对象而不是一个,这是一个选项)但我需要知道是否可以编组单个对象并维护xi:include(或重新引入它)并导出为两个(或者更多)xml文件.
这甚至可能吗?如果有任何提示/想法?
谢谢
更新:
我一直在研究这个(我在询问前研究过).我确实找到了这个教程http://tutorial.waycoolsearch.com/java/jaxb2.php似乎有我的答案,但唉,当我编辑文件时,它需要两个并制作一个.
下面我将演示如何使用XmlAdapter来支持此用例的编组和解组.XmlAdapter(IncludeFruitAdapter)
XmlAdapter可用于此用例.
import java.io.File; import javax.xml.bind.*; import javax.xml.bind.annotation.*; import javax.xml.bind.annotation.adapters.XmlAdapter; public class IncludeFruitAdapter extends XmlAdapter<IncludeFruitAdapter.Include, Fruit> { private JAXBContext jc; private String href = "fruit.xml"; public IncludeFruitAdapter() { try { jc = JAXBContext.newInstance(Fruit.class); } catch(Exception e) { throw new RuntimeException(e); } } public static class Include { @XmlAttribute public String href; @XmlElement(namespace="http://www.w3.org/2001/XInclude") public Fallback fallback; } public static class Fallback { @XmlElementRef public Fruit value; } @Override public Include marshal(Fruit fruit) throws Exception { File xml = new File(href); Marshaller marshaller = jc.createMarshaller(); marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); marshaller.marshal(fruit, xml); Include include = new Include(); include.href = href; include.fallback = new Fallback(); include.fallback.value = new Fruit(); return include; } @Override public Fruit unmarshal(Include include) throws Exception { File xml = new File(include.href); Unmarshaller unmarshaller = jc.createUnmarshaller(); try { return (Fruit) unmarshaller.unmarshal(xml); } catch(Exception e) { return include.fallback.value; } } }
树
@XmlJavaTypeAdapter用于引用XmlAdapter.
import javax.xml.bind.annotation.*; import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter; @XmlRootElement @XmlAccessorType(XmlAccessType.FIELD) public class Tree { @XmlJavaTypeAdapter(IncludeFruitAdapter.class) @XmlElement(name="include", namespace="http://www.w3.org/2001/XInclude") private Fruit fruit; }
水果
import javax.xml.bind.annotation.*; @XmlRootElement @XmlAccessorType(XmlAccessType.FIELD) public class Fruit { private String name; }
演示
下面是一些演示代码,您可以运行以证明一切正常:
import java.io.File; import javax.xml.bind.*; public class Demo { public static void main(String[] args) throws Exception { JAXBContext jc = JAXBContext.newInstance(Tree.class); Unmarshaller unmarshaller = jc.createUnmarshaller(); File xml = new File("input.xml"); Tree tree = (Tree) unmarshaller.unmarshal(xml); Marshaller marshaller = jc.createMarshaller(); marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); marshaller.marshal(tree, System.out); } }