XML转换 – XSL模板匹配多个条件

我正在尝试修改calimero中的ets4_import以匹配旧的ETS4项目和新项目.

是否可以修改

<xsl:template match="/"  xmlns:b="http://knx.org/xml/project/11">

喜欢的东西

<xsl:template match="/"  xmlns:b="http://knx.org/xml/project/11 or http://knx.org/xml/project/10">

XML文件要么以.开头

<?xml version="1.0" encoding="utf-8"?>
<KNX xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" CreatedBy="ETS4" ToolVersion="ETS 4.0.3 (Build 3250)" xmlns="http://knx.org/xml/project/11">

要么

<?xml version="1.0"?>
<KNX xmlns="http://knx.org/xml/project/10" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" CreatedBy="ETS4" ToolVersion="4.0.1387.12605">

Here是完整的XSL文件.

有谁能够帮我？

谢谢

UPDATE

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:b10="http://knx.org/xml/project/10" xmlns:b="http://knx.org/xml/project/11" >
    <xsl:output method="xml" version="1.0" encoding="iso-8859-1" indent="yes"/>
    <xsl:template match="/">
        <xsl:for-each select="b:KNX/b:Project/b:Installations/b:Installation/b:Topology">
            <datapoints>
            <xsl:for-each select="b:Area/b:Line/b:DeviceInstance/b:ComObjectInstanceRefs/b:ComObjectInstanceRef">
                <xsl:sort select="b:Connectors/b:Send/@GroupAddressRefId"/>
                <xsl:if test="not(preceding::b:Connectors/b:Send/@GroupAddressRefId = current()/b:Connectors/b:Send/@GroupAddressRefId)">
                    <xsl:for-each select="b:Connectors">
                        <xsl:variable name="verz" select="document(concat(substring(../@RefId,0,7),'/',substring-before(../@RefId, '_O'), '.xml'))/b:KNX/b:ManufacturerData/b:Manufacturer/b:ApplicationPrograms/b:ApplicationProgram/b:Static/b:ComObjectTable/b:ComObject[@Id = ../../b:ComObjectRefs/b:ComObjectRef[@Id = current()/../@RefId]/@RefId]" /> 
                        <xsl:variable name="grosse">

是否有可能定义

b: = b: | b10:

这样我就不必更改完整的文件了

我认为你在寻找的是：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:b10="http://knx.org/xml/project/10" xmlns:b11="http://knx.org/xml/project/11">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
    <xsl:template match="b10:MyElement|b11:Element">
      <!-- Template code... -->
    </xsl:template>
</xsl:stylesheet>

虽然因为你匹配根元素,并且你一次只转换一个XML文档,但我没有看到问题,因为/在任何情况下都会匹配根元素.