使用XSL转换(XML到XML)包装多个列表元素序列

<chapter someAttributes="someValues">
    <title>someTitle</title>

    <p>multiple paragraphs</p>
    <p>...</p>

    <li>
        <p>- some text</p>
    </li>
    <li>
        <p>- some other text</p>
    </li>
    <!-- another li elements -->

    <p>multiple other paragraphs</p>
    <p>...</p>

    <li>
        <p>1. some text</p>
    </li>
    <li>
        <p>2. some other text</p>
    </li>
    <!-- another li elements -->

    <p>multiple other paragraphs</p>
    <p>...</p>

    <!-- there are other elements such as table, illustration, ul etc. -->  
</chapter>

我想要的是根据一些语义和返回包装的XML来包装每个分散的(我的意思是段落,表格,插图等)li元素序列与ol或ul元素.

>如果段落中的第一个字符等于 – ,那么它应该是带有mark =“DASH”属性的ul
>如果段落以1.,2.,3等开头,那么我想要ol with numeration =“ARABIC”

例如(它只是一个序列)：

<ul mark="DASH">
    <li>
        <p> some text</p>
    </li>
    <li>
        <p> some other text</p>
    </li>
<ul>

如你所见,我需要从所有段落中删除“标记字符”,即 – 或1.,2.,3等.

输入XML比我描述的更复杂(嵌套序列,表元素中的内部序列),但我正在寻找一些想法,特别是如何捕获&处理具有这种语义的特定序列.

我想要输出XML具有完全相同的顺序,只需要包装li元素.如果需要,可以使用XSLT 2.0 / EXSLT.

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="2.0">

  <xsl:output indent="yes"/>

  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@*, node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="chapter">
    <xsl:copy>
      <xsl:for-each-group select="*" group-adjacent="boolean(self::li)">
        <xsl:choose>
          <xsl:when test="current-grouping-key() and ./p[1][starts-with(., '-')]">
            <ul mark="DASH">
              <xsl:apply-templates select="current-group()"/>
            </ul>
          </xsl:when>
          <xsl:when test="current-grouping-key() and ./p[1][matches(., '[0-9]\.')]">
            <ol numeration="arabic">
              <xsl:apply-templates select="current-group()"/>
            </ol>
          </xsl:when>
          <xsl:otherwise>
            <xsl:copy-of select="current-group()"/>
          </xsl:otherwise>
        </xsl:choose>
      </xsl:for-each-group>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="li/p/text()[1]">
    <xsl:value-of select="replace(., '^(-|[0-9]\.)', '')"/>
  </xsl:template>

</xsl:stylesheet>

当我使用Saxon 9.3和样式表以及样本输入时

<chapter someAttributes="someValues">
    <title>someTitle</title>

    <p>multiple paragraphs</p>
    <p>...</p>

    <li>
        <p>- some text</p>
    </li>
    <li>
        <p>- some other text</p>
    </li>
    <!-- another li elements -->

    <p>multiple other paragraphs</p>
    <p>...</p>

    <li>
        <p>1. some text</p>
    </li>
    <li>
        <p>2. some other text</p>
    </li>
    <!-- another li elements -->

    <p>multiple other paragraphs</p>
    <p>...</p>

    <!-- there are other elements such as table, illustration, ul etc. -->  
</chapter>

我得到以下输出：

<?xml version="1.0" encoding="UTF-8"?>
<chapter>
   <title>someTitle</title>
   <p>multiple paragraphs</p>
   <p>...</p>
   <ul mark="DASH">
      <li>
        <p> some text</p>
      </li>
      <li>
        <p> some other text</p>
      </li>
   </ul>
   <p>multiple other paragraphs</p>
   <p>...</p>
   <ol numeration="arabic">
      <li>
        <p> some text</p>
      </li>
      <li>
        <p> some other text</p>
      </li>
   </ol>
   <p>multiple other paragraphs</p>
   <p>...</p>
</chapter>