如果导入不存在,XSLT将当前插入导入 ?xml version="1.0" encoding="utf-8"?Project DefaultTargets="Build" ToolsVersion="4.0" xmlns="http://schemas.microsoft.com/developer/msbuild/2003" ... ... Import Project="$(SolutionDir)BuildSha
<?xml version="1.0" encoding="utf-8"?> <Project DefaultTargets="Build" ToolsVersion="4.0" xmlns="http://schemas.microsoft.com/developer/msbuild/2003"> ... ... <Import Project="$(SolutionDir)BuildShared.targets" /> </Project>
我需要它将它作为第一个节点插入
<?xml version="1.0" encoding="utf-8"?> <Project DefaultTargets="Build" ToolsVersion="4.0" xmlns="http://schemas.microsoft.com/developer/msbuild/2003"> <Import Project="$(SolutionDir)BuildShared.targets" /> ... ... </Project>
template.xsl;
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ms="http://schemas.microsoft.com/developer/msbuild/2003"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match='@*|node()'> <xsl:copy> <xsl:apply-templates select='@*|node()'/> </xsl:copy> </xsl:template> <xsl:template match="/ms:Project[not(ms:Import[@Project='$(SolutionDir)BuildConfiguration.targets'])]"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> <Import xmlns="http://schemas.microsoft.com/developer/msbuild/2003" Project="$(SolutionDir)BuildConfiguration.targets"/> </xsl:copy> </xsl:template> </xsl:stylesheet>
交换导入和apply-templates行给出;
运行时错误:文件template.xsl第9行元素副本
必须在任何子节点之前添加属性节点到元素.
只需为node()和@ *分别执行xsl:apply-templates:<xsl:template match="/ms:Project[not(ms:Import[@Project='$(SolutionDir)BuildConfiguration.targets'])]"> <xsl:copy> <xsl:apply-templates select="@*"/> <Import xmlns="http://schemas.microsoft.com/developer/msbuild/2003" Project="$(SolutionDir)BuildConfiguration.targets"/> <xsl:apply-templates select="node()"/> </xsl:copy> </xsl:template>