我正在寻找一个解决方案,以便仍然可以使用来自react-router的链接,而不是在测试href属性值时. 实际上,我有一些根据上下文改变路线的组件.但是,当我测试href属性值时,返回的唯一内容是
实际上,我有一些根据上下文改变路线的组件.但是,当我测试href属性值时,返回的唯一内容是null.
但是,当我使用a时,它会返回预期值.
这是一个失败的测试:
import React from 'react'; import {Link} from 'react-router'; import TestUtils from 'react-addons-test-utils'; import expect from 'must'; const LINK_LOCATION = '/my_route'; class TestComponent extends React.Component { render() { return ( <div> <Link className='link' to={LINK_LOCATION}/> <a className='a' href={LINK_LOCATION}/> </div> ); } } describe('Url things', () => { it('should return me the same href value for both link and a node', () => { const test_component = TestUtils.renderIntoDocument(<TestComponent/>); const link = TestUtils.findRenderedDOMComponentWithClass(test_component, 'link'); const a = TestUtils.findRenderedDOMComponentWithClass(test_component, 'a'); expect(link.getAttribute('href')).to.eql(a.getAttribute('href')); }); });
输出:AssertionError:null必须等效于“/ my_route”
来自React-router的知道人员回答看他们如何测试Link,但是他们没有可以改变href属性值的动态上下文.
所以我做了类似的事情:
class ComponentWrapper extends React.Component { constructor(props) { super(props); this.state = {}; } set_props(props) { this.setState({props}); } render() { if (this.state.props) { return <Component {...this.state.props}/>; } return null; } }
但是现在,从我的组件助手:
render_into_document() { const full_component_props = { location: this.location, widget_categories: this.widget_categories }; node = document.createElement('div'); this.component = render(( <Router history={createHistory('/')}> <Route path='/' component={ComponentWrapper} /> </Router> )); this.component.set_props(full_component_props); return this; }
我不能把手放在this.component上以改变道具.我怎么能这样做?
我只是看了 howreact-router
tests <Link />
并为我的案例提出了这个问题:
import test from 'ava' import React from 'react' import { render } from 'enzyme' import { Router, Route } from 'react-router' import createHistory from 'history/lib/createMemoryHistory' import SkipToXoom from '../skip-to-xoom' test('the rendered button redirects to the proper URL when clicked', t => { const toCountryData = { countryName: 'India', countryCode: 'IN' } const div = renderToDiv({ toCountryData, disbursementType: 'DEPOSIT', userLang: 'en_us' }) const { attribs: { href } } = div.find('a')[0] t.true(href.includes(encodeURIComponent('receiveCountryCode=IN'))) t.true(href.includes(encodeURIComponent('disbursementType=DEPOSIT'))) t.true(href.includes(encodeURIComponent('languageCode=en'))) }) /** * Render the <SkipToXoom /> component to a div with the given props * We have to do some fancy footwork with the Router component to get * the Link component in our SkipToXoom component to render out the href * @param {Object} props - the props to apply to the component * @returns {Element} - the div that contains the element */ function renderToDiv(props = {}) { return render( <Router history={createHistory('/')}> <Route path="/" component={() => <SkipToXoom {...props} userLang="en" />} /> </Router> ) }
我希望这对你有所帮助!