参见英文答案 Convert js Array() to JSon object for use with JQuery .ajax5个 我正在尝试通过jQuery.ajax将JavaScript数组发送到PHP页面,但该数组仅使用空值发送. 如果我在Chrome上打开F12控制台并检查JS对象
我正在尝试通过jQuery.ajax将JavaScript数组发送到PHP页面,但该数组仅使用空值发送.
如果我在Chrome上打开F12控制台并检查JS对象,它就在那里.全部填满了.但是当我使用ChromePhp工具记录PHP变量时,它只显示空白值(同样,如果我遍历php-array,回显它的值,我得到所有空白).
我在这里很困惑.
这是我的示例代码：
<?php
include 'ChromePhp.php';
if (isset($_GET['newUsers'])) {
$newUsers = $_GET['newUsers'];
ChromePhp::log($newUsers);
} else { ?>
<html>
<body>
<script src="js/jquery-2.0.3.min.js"></script>
<script type="text/javascript">
var newUsers = [];
newUser = [];
newUser['nome'] = 'alvaro';
newUser['idade'] = '34';
newUsers.push(newUser);
newUser1 = [];
newUser1['nome'] = 'bia';
newUser1['idade'] = '7';
newUsers.push(newUser1);
newUser2 = [];
newUser2['nome'] = 'alice';
newUser2['idade'] = '2';
newUsers.push(newUser2);
$.ajax({
url: "testcookie.php",
type: "GET",
data: {
'newUsers[]': newUsers
}
});
</script>
</body>
</html>
<?php } ?>
根据第一条评论更新.现在我得传递对象,但不知道如何读取它的属性.已经尝试了$user [‘nome’]没有结果.
<?php
include 'ChromePhp.php';
if (isset($_POST['newUsers'])) {
$newUsers = $_POST['newUsers'];
foreach ($newUsers as $user) {
# code...
# HOW DO I READ THE nome AND idade VALUES HERE?
}
} else { ?>
<html>
<body>
<script src="js/jquery-2.0.3.min.js"></script>
<script type="text/javascript">
//var newUsersObj = {};
var newUsers = [];
newUser = {};
newUser['nome'] = 'alvaro';
newUser['idade'] = '34';
newUsers.push(newUser);
newUser1 = {};
newUser1['nome'] = 'bia';
newUser1['idade'] = '7';
newUsers.push(newUser1);
newUser2 = {};
newUser2['nome'] = 'alice';
newUser2['idade'] = '2';
newUsers.push(newUser2);
$.ajax({
url: "testcookie.php",
type: "POST",
data: {
'newUsers[]': newUsers
},
success: function () {
},
error: function () {
}
});
</script>
</body>
</html>
<?php } ?>
只需传递数组或对象,jQuery就会自动将数组或对象转换为正确的参数,如a = [1,2] – >一个[] = 1&安培;一个[] = 2
data: {
'newUsers': newUsers
}
实现这一目标的内部功能是http://api.jquery.com/jQuery.param/