export const USER_KEY = "isLoggedIn";export const phoneVerified = () = AsyncStorage.setItem(USER_KEY, 1);export const userInfoVerified = () = AsyncStorage.setItem(USER_KEY, 2); 我已经使用上面的函数来存储值,而使用下面的函数
export const USER_KEY = "isLoggedIn"; export const phoneVerified = () => AsyncStorage.setItem(USER_KEY, 1); export const userInfoVerified = () => AsyncStorage.setItem(USER_KEY, 2);
我已经使用上面的函数来存储值,而使用下面的函数来获取值.
export const isSignedIn = () => {
return new Promise((resolve, reject) => {
AsyncStorage.getItem(USER_KEY)
.then(res => {
console.log("from isSignedIn : "+res); //res is showing null.
if (res !== null) {
resolve(res);
} else {
resolve(0);
}
})
.catch(err => reject(err));
});
};
为什么这总是返回null?我正在尝试async / await但仍然是null.我想某种方式数据不存储.
我担心你只能存储字符串.请参阅本 React Native AsyncStorage storing values other than strings和本 https://facebook.github.io/react-native/docs/asyncstorage.html#setitem谢谢.
