reactjs – 如何将prop值分配给react中的状态

我有一个从另一个React组件启动的叠加层,它有一个也会自行更改的按钮.当用户单击按钮时,会发生更改,然后按钮会更改其类名.它还向作为叠加层的子组件发送prop值.叠加层根据属性添加一个类,如果单击它. Everthing工作得很好,但现在我必须做另外一件事.当用户点击叠加层时,它必须关闭.在此更改之前,所有内容都适用于我之前提到的按钮.

那么这是按钮组件：

export default class StatusBarButton extends React.Component {

    constructor(props) {
        super(props)
        this.state = {active: false}
        this.handleClick = this.handleClick.bind(this)
    }

    handleClick() {
        this.setState({ active: !this.state.active });
    }

    render() {
        var cx = require('classnames');
        var button = cx ({
            'statusbar-button-container' : true,
            'active' : this.state.active
        });
        var animation = cx ({
            'statusbar-button-cross-image' : true,
            'rotate' : true,
            'active' : this.state.active
        });

        return (
            <div className="astatusbar-center-wrapper">
                <div className={button} onClick={this.handleClick}>
                    <img src="images/navbar-element-icon-cross.png" className={animation}/>
                </div>      
                <OverlayView isOpen={this.state.active} />
            </div>
        );
    }
}

而这就是目前的叠加：

export default class OverlayView extends React.Component {
    constructor (props){
        super(props);
        this.state = {open: false}
        this.setState({ open: this.props.isOpen });
    }



    render() {
        var cx = require('classnames');
        var overlay = cx({
            'overlay': true,
            'overlay-slidedown': true,
            'open': this.state.open
        });

        return (    
            <div className={overlay} onClick={this._closeOverlay}>
                <div className="overlay-menu-wrapper">
                    <OverlayNewInvoiceButton />
                    <OverlayNewBudgetButton />
                    <OverlayNewTicketButton />
                </div>
            </div>
        );
    }
}

如你所见,我试图获得道具价值并将其分配给州,但它不起作用.如何将prop值分配给状态并使用它？

问候,
J.P

您缺少OverlayView组件中的componentWillReceiveProps(props)方法.

export default class OverlayView extends React.Component {
    constructor (props){
        super(props);
        this.state = {open: props.isOpen}
    }

    componentWillReceiveProps(props) {
        this.setState({open: props.isOpen});
    }

    render() {
        let open = '';
        if (this.state.open === true) {
            open = 'open';
        }

        let overlayClass = `overlay overlay-slidedown ${open}`;

        return (    
            <div className={overlayClass} onClick={this._closeOverlay}>
                <div className="overlay-menu-wrapper">
                    <span>{open}</span>
                </div>
            </div>
       );
    }
}

完整的工作示例：
https://codesandbox.io/s/35wLR4nA