如果我附加任何额外的验证方法,我在保存运行for循环的项目时遇到问题.基本上,我正在构建一个Instagram API应用程序,允许编辑删除不合适的照片.照片从Instagram中分批抽出20张并显示给编
          为了不将列入黑名单的照片重新出现在Feed上,在将项目保存到主照片数据库之前,需要根据黑名单检查照片的Instagram ID.为此,我使用的是Schema方法.
现在的问题是,我只将一张照片保存到数据库中.如果我拿出方法检查,那么我得到全部20.
这是我的主要创建控制器:
exports.create = function(req, res) {
var topic = req.body.topic || 'nyc';
var path = 'https://api.instagram.com/v1/tags/' + topic + '/media/recent?client_id=' + 'XXXXXXXXXX';
request.get({url: path}, function(err, response){
  if (err){
    console.log('Failed to get data: ', err);
    return res.status(400).json({error: 'Not allowed'});
  }
  else{
    // ------------------------------------------------
    // Make sure we have JSON
    //
    var body = JSON.parse(response.body);
    // ------------------------------------------------
    // Loop through each response
    //
    for (var i = 0; i < body.data.length; i++ ){
      var photoData = body.data[i];
      // ------------------------------------------------
      // If there is no caption, skip it
      //
      if (!photoData.caption){
        text = '';
      }
      else{
        text = photoData.caption;
      }
      // ------------------------------------------------
      // Create new photo object
      //
      var photo = new Photo({
        link: photoData.link,
        username: photoData.user.username,
        profilePicture: photoData.user.profile_picture,
        imageThumbnail: photoData.images.thumbnail.url,
        imageFullsize: photoData.images.standard_resolution.url,
        caption: text,
        userId: photoData.user.id,
        date: photoData.created_time,
        _id: photoData.id
      });
      photo.checkBlacklist(function(err, blacklist){
        if (!blacklist){
          photo.save(function(err, item){
            if (err){
              console.log(err);
            }
            console.log('Saved', item);
          })
        }
      });
      // -------------------------------------------------
      //
      // Save
      // 
      // -------------------------------------------------
    } // END FOR LOOP
    console.log('Photos saved');
    return res.json(201, {msg: 'Photos updated'} );
  }
});
}; 
 这是我的照片架构:
'use strict';
var mongoose = require('mongoose'),
Schema = mongoose.Schema;
var Blacklist = require('../blacklist/blacklist.model');
var PhotoSchema = new Schema({
  created: {type: Date, default: Date.now()},
  date: String,
  link: String,
  username: String,
  profilePicture: String,
  imageThumbnail: {type: String, unique: true},
  imageFullsize: String,
  caption: String,
  userId: String,
  _id: {type: String, unique: true}
});
PhotoSchema.methods.checkBlacklist = function(callback){
  return Blacklist.findById(this._id, callback);
};
module.exports = mongoose.model('Photo', PhotoSchema); 
 奇怪的是,我在创建控制器中获取了所有20个保存的控制台消息:
    console.log(‘已保存’,项目);
但实际上只保存了一张照片.有什么想法吗?
谢谢
当您必须为数组中的项执行相同的异步任务时,请不要使用常规for循环.查看 async.each,它更适合您的场景,例如(只是代码的其他部分):var body = JSON.parse(response.body);
async.each(body.data, function (photoData, callback) {
  // ------------------------------------------------
  // If there is no caption, skip it
  //
  if (!photoData.caption){
    text = '';
  }
  else{
    text = photoData.caption;
  }
  // ------------------------------------------------
  // Create new photo object
  //
  var photo = new Photo({
    link: photoData.link,
    username: photoData.user.username,
    profilePicture: photoData.user.profile_picture,
    imageThumbnail: photoData.images.thumbnail.url,
    imageFullsize: photoData.images.standard_resolution.url,
    caption: text,
    userId: photoData.user.id,
    date: photoData.created_time,
    _id: photoData.id
  });
  photo.checkBlacklist(function(err, blacklist){
    if (!blacklist){
      photo.save(function(err, item){
        if (err){
          console.log(err);
        }
        console.log('Saved', item);
        callback();
      });
    }
  });
}, function (error) {
  if (error) res.json(500, {error: error});
  console.log('Photos saved');
  return res.json(201, {msg: 'Photos updated'} );
}); 
 别忘了安装
npm install async
并要求异步:
var async = require('async');
        
             