https://www.luogu.org/problem/P1919 #includecstdio#includealgorithm#includecstring#includecomplexusing namespace std;int n;typedef complexdouble cd;#define maxl 2097153#define PI 3.14159265358979char s1[maxl],s2[maxl];cd a[maxl];cd b[maxl];
https://www.luogu.org/problem/P1919
#include<cstdio> #include<algorithm> #include<cstring> #include<complex> using namespace std; int n; typedef complex<double> cd; #define maxl 2097153 #define PI 3.14159265358979 char s1[maxl],s2[maxl]; cd a[maxl]; cd b[maxl]; int rev[maxl]; void get_rev(int bit) { for(int i=0;i<(1<<bit);i++) rev[i]=(rev[i>>1]>>1)|((i&1)<<(bit-1)); } void fft(cd *a,int n,int dft) { for(int i=0;i<n;i++) if(i<rev[i]) swap(a[i],a[rev[i]]); for(int step=1;step<n;step<<=1) { cd wn=exp(cd(0,dft*PI/step)); for(int j=0;j<n;j+=step<<1) { cd wnk(1,0); for(int k=j;k<j+step;k++) { cd x=a[k]; cd y=wnk*a[k+step]; a[k]=x+y; a[k+step]=x-y; wnk*=wn; } } } if(dft==-1) for(int i=0;i<n;i++) a[i]/=n; } int output[maxl]; int main() { //freopen("fft.in","r",stdin); scanf("%s%s",s1,s2); int l1=strlen(s1); int l2=strlen(s2); int s=2,bit=1; for(bit=1;(1<<bit)<l1+l2-1;bit++)s<<=1;//maybe wiping the"-1" is better for(int i=0;i<l1;i++) a[i]=(double)(s1[l1-i-1]-‘0‘); for(int i=0;i<l2;i++) b[i]=(double)(s2[l2-i-1]-‘0‘); //for(int i=0;i<8;i++) printf("%d %d\n",i,rev[i]); get_rev(bit); fft(a,s,1); fft(b,s,1); for(int i=0;i<s;i++) a[i]*=b[i]; fft(a,s,-1); for(int i=0;i<s;i++) { output[i]+=(int)(a[i].real()+0.5);//取实数四舍五入,此时虚数部分应当为0或由于浮点误差接近0 output[i+1]+=output[i]/10; output[i]%=10; } int i; for(i=l1+l2;!output[i]&&i>=0;i--); if(i==-1) printf("0"); for(;i>=0;i--) printf("%d",output[i]); putchar(‘\n‘); }