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从单击面向对象的PyGame按钮调用PyGame函数

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import pygame as pgimport syspg.init()buttonFont = pg.font.SysFont("garamond", 25)screenGray = pg.Color('gray80')buttonGray2 = pg.Color('gray50')textColour = pg.Color('navy')screen = pg.display.set_mode((800, 600))clock = pg.time.Clock()cla
import pygame as pg
import sys

pg.init()

buttonFont = pg.font.SysFont("garamond", 25)

screenGray = pg.Color('gray80')
buttonGray2 = pg.Color('gray50')
textColour = pg.Color('navy')

screen = pg.display.set_mode((800, 600))
clock = pg.time.Clock()

class Button(pg.sprite.Sprite):
    def __init__(self, text, x, y, width, height, colour):
        super().__init__()
        self.image = pg.Surface((width, height))
        self.image.fill(colour)
        self.rect = self.image.get_rect()
        txt = buttonFont.render(text, True, textColour)
        txtRect = txt.get_rect(center = self.rect.center)
        self.image.blit(txt, txtRect)
        self.rect.topleft = x, y

    def isPressed(self, event):
        if event.type == pg.MOUSEBUTTONDOWN:
            if self.rect.collidepoint(event.pos):
                return True
        return False

def FrontPage():
    screen.fill(screenGray)

    Continue = Button('Continue', 105, 455, 120, 50, buttonGray2)
    buttonsGroup1 = pg.sprite.Group(Continue)

    while True:
        for event in pg.event.get():
            if event.type == pg.QUIT:
                pg.quit()
                sys.exit()
            elif Continue.isPressed(event):
                Menu()

        buttonsGroup1.draw(screen)

        pg.display.flip()
        clock.tick(60)

def Menu():
    screen.fill(screenGray)

    Scytale = Button('Scytale', 105,105,140,65, buttonGray2)
    Caesar = Button('Caesar', 330,105,140,65, buttonGray2)
    Vigenere = Button('Vigenere', 555,105,140,65, buttonGray2)
    Enigma = Button('Enigma', 105,430,140,65,buttonGray2)
    PublicKey = Button('Public Key', 330,430,140,65, buttonGray2)
    Rijndael = Button('Rijndael', 555,430,140,65, buttonGray2)

    buttonsGroup2 = pg.sprite.Group(Scytale,Caesar,Vigenere,Enigma,PublicKey,Rijndael)

    while True:
        for event in pg.event.get():
            if event.type == pg.QUIT:
                pg.quit()
                sys.exit()

        buttonsGroup2.draw(screen)
        clock.tick(60)

FrontPage()

上面是我的FrontPage的剥离代码,其上有一个按钮,当点击它时,应该将用户带到菜单屏幕,其中显示6个按钮以移动到用户选择的加密方法.

但是,当我按下继续按钮时,没有任何反应.

是因为Button Class有问题吗?
或者是否有其他东西使按钮停止工作?

提前致谢

你必须在菜单功能中调用pg.display.flip().

我还对代码结构有一点建议.我会使用另一个函数或类(在本例中为main)来管理不同的场景.所以我首先将当前场景函数分配给变量并在主while循环中调用它.场景完成后,我返回下一个场景并将其分配给场景变量以交换场景.如果您只是直接从另一个场景中调用下一个函数,那么这将避免潜在的递归错误(尽管在简单的游戏或应用程序中你不太可能超过1000的递归限制).

import pygame as pg


pg.init()
screen = pg.display.set_mode((600, 400))
clock = pg.time.Clock()
BLUE = pg.Color('dodgerblue3')
ORANGE = pg.Color('sienna3')


def front_page():
    while True:
        for event in pg.event.get():
            if event.type == pg.QUIT:
                return None
            # Press a key to return the next scene.
            elif event.type == pg.KEYDOWN:
                return menu

        screen.fill(BLUE)
        pg.display.flip()
        clock.tick(60)


def menu():
    while True:
        for event in pg.event.get():
            if event.type == pg.QUIT:
                return None
            # Press a key to return the next scene.
            elif event.type == pg.KEYDOWN:
                return front_page

        screen.fill(ORANGE)
        pg.display.flip()
        clock.tick(60)


def main():
    scene = front_page  # Set the current scene.
    while scene is not None:
        # Execute the current scene function. When it's done
        # it returns either the next scene or None which we
        # assign to the scene variable.
        scene = scene()


main()
pg.quit()
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