自动化Xcode 4.1的AppleScript语法清理,构建然后运行

我明白,这个问题已经有问题了,但是阅读了我能找到的东西(特别是这个： Tell AppleScript To Build XCode Project),他们似乎都是几岁,答案似乎不适用于当前版本Xcode中.

与链接的问题类似,我试图自动打开Xcode项目,构建它,然后在iPhone模拟器(v4.3)中运行应用程序.该项目是Selenium项目的iPhoneDriver(详见这里：http://code.google.com/p/selenium/wiki/IPhoneDriver)

根据另一个问题的答案,我写了以下脚本：

tell application "Xcode"
    open "/Users/<username>/Documents/Code/Selenium/iphone/iWebDriver.xcodeproj"
    tell project "iWebDriver"
         clean
         build
         try
             debug
         end try
    end tell
end tell

不幸的是,当我运行这个我得到以下内容：

tell application "Xcode"
open "/Users/ben.adderson/Documents/Code/Selenium/iphone/iWebDriver.xcodeproj"
    --> project document "iWebDriver.xcodeproj"
clean project "iWebDriver"
    --> missing value
build project "iWebDriver"
    --> missing value
debug project "iWebDriver"
    --> error number -1708
end tell

如果我只运行打开的命令,Xcode打开项目没有问题.但是,一旦我包含脚本的其余部分,Dock中的Xcode图标就会弹出,但是除了AppleScript编辑器之外,还有这一点.

有人建议我做错了什么？这是我第一次使用AppleScript或Xcode,所以我很努力地诊断问题.

我试过看Xcode AppleScript字典,但没有工作的例子,我无法确定我需要的语法.

提前感谢任何帮助！

使用AppleScript和命令行工具(xcodebuild)的混合,我想出了这一点：

-- This script will clean, build then run the project at the path below.
-- You will need to slightly modify this script if you have more than one xcodeproject at this path

set pathOfXcodeProject to "/Users/<username>/Documents/Code/Selenium/iphone/iWebDriver.xcodeproj"
-- End of configuration



do shell script "cd " & pathOfXcodeProject & " && /usr/bin/xcodebuild clean build "

tell application "Xcode"

    open pathOfXcodeProject
    activate
end tell

tell application "System Events"
    get system attribute "sysv"
    if result is greater than or equal to 4144 then -- Mac OS X 10.3.0
        if UI elements enabled then
            tell application process "Xcode"
                click menu item "Run" of menu 1 of menu bar item "Product" of menu bar 1

            end tell
        else
            beep
            display dialog "GUI Scripting is not enabled" & return & return & "Open System Preferences and check Enable Access for Assistive Devices in the Universal Access preference pane, then run this script again." with icon stop
            if button returned of result is "OK" then
                tell application "System Preferences"
                    activate
                    set current pane to pane "com.apple.preference.universalaccess"
                end tell
            end if
        end if
    else
        beep
        display dialog "This computer cannot run this script" & return & return & "The script uses GUI Scripting technology, which requires an upgrade to Mac OS X 10.3 Panther or newer." with icon caution buttons {"Quit"} default button "Quit"
    end if
end tell

让我知道,如果这适用于你.我在Lion的Xcode 4.2.1测试了一个iPhone项目.