如果我运行此代码,我得到主题错误消息.但为什么?如何避免让C类拥有其父级插槽? class A(): __slots__ = ['slot1']class B(): __slots__ = ['slot2']class C(A, B): __slots__ = [] 简单地说,你就是做不到. 如
class A(): __slots__ = ['slot1'] class B(): __slots__ = ['slot2'] class C(A, B): __slots__ = []简单地说,你就是做不到.
如Documentation所述,
Multiple inheritance with multiple slotted parent classes can be used, but only one parent is allowed to have attributes created by slots (the other bases must have empty slot layouts) – violations raise TypeError.
__slots__背后的想法是为实例的内存布局中的每个属性保留特定的插槽. A和B正在尝试为slot1和slot2属性保留其内存布局的相同部分,并且C不能为两个属性保留相同的内存.它只是不兼容.
感谢JCode在评论中提到的,以下方法被修改为正确.
但总有办法,我个人更喜欢使用包含所有必需插槽的公共库,如果有多个继承类,则需要__slots__.
import pympler.asizeof class base(): __slots__ = ['a','b'] class A(base): __slots__ = [] class B(base): __slots__ = [] class C(A,B): __slots__ = [] class D(): pass #Update bb = base() bb.a = 100 bb.b = 100 print(pympler.asizeof.asizeof(bb)) a = A() a.a = 100 a.b = 100 print(pympler.asizeof.asizeof(a)) c = C() c.a = 100 c.b = 100 print(pympler.asizeof.asizeof(c)) d = D() d.a = 100 d.b = 100 print(pympler.asizeof.asizeof(d))
更新4个值将是88,88,88,312.虽然__slots__保留.