目录 1. 案例 2. APDL分析 1. 案例 一个温度为 300℃ 的铜环和一个温度为 200℃ 的铁环，放置到22℃的水中进行淬火。水桶为铁质的圆形。分析中忽略水的流动。 材料参数 热性能 铜 铁 水
目录
- 1. 案例
- 2. APDL分析
1. 案例
一个温度为300℃的铜环和一个温度为200℃的铁环，放置到22℃的水中进行淬火。水桶为铁质的圆形。分析中忽略水的流动。
材料参数
因为忽略了水的流动，故可将水看为一种材料，直接进行分析
2. APDL分析
finish /clear !==============第一步：进行稳态二维轴对称分析=============================== /filname,quench /prep7 et,1,plane55 ! 选择单元类型 keyopt,1,3,1 ! 设置为轴对称分析 ! 定义材料热性能参数 mp,kxx,1,383 mp,dens,1,8889 mp,c,1,390 ! 定义铜的热物理性能参数 mp,kxx,2,70 mp,dens,2,7837 mp,c,2,448 ! 定义铁的热物理性能参数 mp,kxx,3,0.61 mp,dens,3,996 mp,c,3,4185 ! 定义水的热物理性能参数 rectng,0,0.08,0,0.01 rectng,0.08,0.1,0,0.01 rectng,0.1,0.12,0,0.01 rectng,0.12,0.14,0,0.01 rectng,0.14,0.15,0,0.01 rectng,0.14,0.15,0.01,0.055 rectng,0.14,0.15,0.055,0.1 rectng,0.14,0.15,0.1,0.15 ! 建立铁箱矩形 rectng,0.08,0.1,0.01,0.055 rectng,0.1,0.12,0.01,0.055 ! 建立铜环 rectng,0.08,0.1,0.055,0.1 ! 建立铁环 rectng,0,0.08,0.01,0.055 rectng,0.12,0.14,0.01,0.055 rectng,0,0.08,0.055,0.1 rectng,0.10,0.12,0.055,0.1 rectng,0.12,0.14,0.055,0.1 rectng,0,0.08,0.1,0.15 rectng,0.08,0.1,0.1,0.15 rectng,0.10,0.12,0.1,0.15 rectng,0.12,0.14,0.1,0.15 ! 建立水几何模型 aglue,all ! 粘接各矩形 esize,0.003,0, ! 定义单元划分尺寸 asel,s,,,1,21,20 asel,a,,,23,29,1 aatt,2,1,1 ! 附于铁箱和铁环的材料属性 asel,s,,,30,33,3 aatt,1,1,1 ! 附于铜环的材料属性 asel,s,,,31,32,1 asel,a,,,34,39,1 asel,a,,,22 aatt,3,1,1 ! 附于水的材料属性 allsel,all mshkey,2 ! 定义映射单元划分类型 amesh,all ! 划分单元 asel,s,,,1,21,20 asel,a,,,23,28,1 asel,a,,,31,32,1 asel,a,,,34,39,1 asel,a,,,22 nsla,,1 d,all,temp,20 ! 施加铁箱和水的温度约束条件 asel,s,,,30,33,3 nsla,,1 d,all,temp,300 ! 施加铜环的温度约束条件 asel,s,,,29 nsla,,1 d,all,temp,200 ! 施加铁环的温度约束条件 allsel,all /solu antype,trans ! 设定为瞬态分析 timint,off ! 关掉时间积分, 即设定为稳态分析 time,0.01 ! 设定只有一个子步的时间很小的载荷步 deltim,0.01 ! 设定求解时间子步 solve ! 求解 !==============第二步：进行瞬态二维轴对称分析=============================== time,3600 ! 设定求解时间 timint,on ! 打开时间积分 deltim,26,2,200 ! 设置时间步长，最大及最小时间步长 autots,on ! 打开自动时间步长 ddelet,all,temp ! 删除稳态分析中定义的节点温度 outres,all,1 ! 将每个子步的值写入数据库文件 solve ! 求解 finish /post1 plnsol,temp,,0
样件上的某点随时间变化的曲线