我似乎无法让这个工作.我想从不同的Web服务器中提取CSV文件以读取我的应用程序.这就是我想要的方式： url = 'http://www.testing.com/test.csv'records = FasterCSV.read(url, :headers = true, :header_converte
url = 'http://www.testing.com/test.csv' records = FasterCSV.read(url, :headers => true, :header_converters => :symbol)
但这不起作用.我试过谷歌搜索,我想出的就是这个摘录：Practical Ruby Gems
所以,我尝试修改如下：
require 'open-uri' url = 'http://www.testing.com/test.csv' csv_url = open(url) records = FasterCSV.read(csv_url, :headers => true, :header_converters => :symbol)
…而且我得到一个无法将Tempfile转换为String错误(来自FasterCSV gem).
谁能告诉我如何使这项工作？
require 'open-uri'
url = 'http://www.testing.com/test.csv'
open(url) do |f|
f.each_line do |line|
FasterCSV.parse(line) do |row|
# Your code here
end
end
end
http://www.ruby-doc.org/core/classes/OpenURI.html
http://fastercsv.rubyforge.org/