我有两个数组: a = [a1, ..., an]b = [b1, ..., bn] 我想从这些数组创建一个对象数组,其中一个对象有字段a和b.所以它看起来像: o = [o1, ..., on] 其中o1.a = a1和o1.b = b1和o2.a = a2和o2.b = b2等等. 现在
a = [a1, ..., an] b = [b1, ..., bn]
我想从这些数组创建一个对象数组,其中一个对象有字段a和b.所以它看起来像:
o = [o1, ..., on]
其中o1.a = a1和o1.b = b1和o2.a = a2和o2.b = b2等等.
现在,我有:
Obj = Struct.new(:a, :b) a = [1, 2, 3, 4] b = [5, 6, 7, 8] objs = [] // Is there a better way of doing the following or is it okay? a.zip(b).each do |ai| objs << Obj.new(ai[0], ai[1])
a.zip(b).map { |args| Obj.new(*args) }
根据你的编辑:
a.zip(b).map { |(a, b)| Obj.new(a, b) }