tl; dr如何使用对象的键获取相应的值? 我很困惑为什么 Atag.where(标签:’品牌’)给了我一个我称之为对象的缺乏更好的术语:# ActiveRecord :: Relation [# Atag id:1,tag:“brand”,created_at:“
我很困惑为什么
Atag.where(标签:’品牌’)给了我一个我称之为对象的缺乏更好的术语:#< ActiveRecord :: Relation [#< Atag id:1,tag:“brand”,created_at:“ 2015-01-31 04:29:20“,updated_at:”2015-01-31 04:29:20“>]>
但是我很难获得密钥的相应值:id.
Atag.where(标记:’品牌’).id和Atag.where(标记:’品牌’)[:id]和Atag.where(标记:’品牌’)(:id)都抛出错误,而在这种情况下我只是想让整数1返回.
我似乎无法回顾,也没有用我的谷歌搜索技能(或缺乏)找到这个基本问题的简洁答案.
谢谢
使用以下查询获取tag =’brand’的ID:Atag.find_by(tag:'brand').id
检查以下变化:
Atag.find(1) #gives you the object with the Atag id = 1 Atag.find(100) #let's say this record does not exist then you will get ActiveRecord::RecordNotFound exception.
更好的选择:
Atag.where(id: 1) #this returns you a relation and it's true you are trying to access only a single object. Hence, you just need to modify it to : Atag.where(id: 1).first #Above one will give you an object of Atag not an association result. # to verfiy you can execute, Atag.where(id: 1).first.class Atag.where(id: 999).first # In this case if there is no record found with id = 999, then it'll return nil which can be easily handled than an exception found while using find method.
使用动态查找器获得相同的味道.
Atag.find_by(id: 1) #gives the Atag with id 1 Atag.find_by_id(1). # same as above. Atag.find_by(id: 999) #if not found then simply returns nil. Atag.find_by(name: 'ruby') #return Atag object with name: 'ruby' Atag.find_by_name('ruby') #same as above.