我厌倦了网络服务. 我有一个非常简单的soap webservice: @Remotepublic interface StudentService{public String sayHello();public ListStudent getStudents();} 和 @Stateless@WebServicepublic class StudentServiceImpl implements S
我有一个非常简单的soap webservice:
@Remote
public interface StudentService
{
public String sayHello();
public List<Student> getStudents();
}
和
@Stateless
@WebService
public class StudentServiceImpl implements StudentService
{
@Override
public String sayHello()
{
return "Hello World";
}
public List<Student> getStudents()
{
List<Student> students = new ArrayList<Student>();
Student st1 = new Student();
st1.setMatricule(1234);
st1.setName("student1");
students.add(st1);
Student st2 = new Student();
st2.setMatricule(5678);
st2.setName("student2");
students.add(st2);
return students;
}
}
和
public class Student implements Serializable
{
private static final long serialVersionUID = 8286393242028201686L;
private int matricule;
private String name;
public int getMatricule()
{
return matricule;
}
public void setMatricule(int matricule)
{
this.matricule = matricule;
}
public String getName()
{
return name;
}
public void setName(String name)
{
this.name = name;
}
}
我在glassfish 3.1下部署服务.
使用glassfish控制台,它正在工作.
<?xml version="1.0" encoding="UTF-8"?>
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
<S:Body>
<ns2:getStudentsResponse xmlns:ns2="http://services.tuto.java.com/">
<return>
<matricule>1234</matricule>
<name>student1</name>
</return>
<return>
<matricule>5678</matricule>
<name>student2</name>
</return>
</ns2:getStudentsResponse>
</S:Body>
</S:Envelope>
使用php它也有效(对于这两种方法).
现在有了一个java客户端:
import javax.xml.namespace.QName;
import org.apache.axis.client.Call;
import org.apache.axis.client.Service;
public class Client
{
public static void main(String[] args) throws Exception
{
String endPoint = "http://localhost:8080/StudentServiceImplService/StudentServiceImpl";
Service service = new Service();
Call call = (Call) service.createCall();
call.setTargetEndpointAddress(new java.net.URL(endPoint));
call.setOperationName(new QName("http://services.tuto.java.com/","sayHello"));
System.out.println(call.invoke(new Object[0]));
Service service2 = new Service();
Call call2 = (Call) service2.createCall();
call2.setTargetEndpointAddress(new java.net.URL(endPoint));
call2.setOperationName(new QName("http://services.tuto.java.com/","getStudents"));
System.out.println(call2.invoke(new Object[0]));
}
}
第一个电话正在工作但不是第二个电话.
Hello World 12-mars-2012 14:53:23 org.apache.axis.client.Call invoke GRAVE: Exception: org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize. at org.apache.axis.encoding.ser.SimpleDeserializer.onStartChild(SimpleDeserializer.java:145) at org.apache.axis.encoding.DeserializationContext.startElement(DeserializationContext.java:1035) at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165) at org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:1141) at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:345) at org.apache.axis.message.RPCElement.getParams(RPCElement.java:384) at org.apache.axis.client.Call.invoke(Call.java:2467) at org.apache.axis.client.Call.invoke(Call.java:2366) at org.apache.axis.client.Call.invoke(Call.java:1812) at Client.main(Client.java:24)
我能做什么 ?
经过大量的时间在网上搜索并尝试不同的解决方案仍然没有任何工作…
有简单的解决方案吗?
谢谢.
编辑:
还试过:
public class SoapClient
{
public static void main(String[] args) throws Exception
{
SOAPMappingRegistry smr = new SOAPMappingRegistry();
BeanSerializer beanSer = new BeanSerializer();
smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("http://services.tuto.java.com/", "StudentServiceImplService"),Student.class, beanSer, beanSer);
Call call = new Call();
call.setSOAPMappingRegistry(smr);
call.setEncodingStyleURI(Constants.NS_URI_SOAP_ENC);
call.setTargetObjectURI("http://services.tuto.java.com/");
call.setMethodName("getStudents");
Response resp;
try
{
resp = call.invoke(new URL("http://8h9l45j:8080/StudentServiceImplService/StudentServiceImpl"), "");
}
catch (SOAPException e)
{
System.err.println("Caught SOAPException (" +
e.getFaultCode() + "): " + e.getMessage());
return;
}
if (!resp.generatedFault())
{
Parameter ret = resp.getReturnValue();
Object value = ret.getValue();
if ( value != null )
{
String[] tlist = (String[])value;
System.out.println();
for ( int i = 0; i < tlist.length; i++ )
System.out.println(tlist[i]);
}
}
else
{
Fault fault = resp.getFault();
System.err.println("Generated fault: ");
System.out.println (" Fault Code = "
+ fault.getFaultCode());
System.out.println (" Fault String = "
+ fault.getFaultString());
}
}
结果如下:
Caught SOAPException (SOAP-ENV:Client): No Deserializer found to deserialize a ':return' using encoding style 'http://schemas.xmlsoap.org/soap/encoding/'.使用soap客户端的第一个响应元素.
问题来自maptypes名称空间:没有名称空间
所以现在,我有
smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("","student"),Student.class, null, new BeanSerializer());
smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("","matricule"),Integer.class, null, new IntDeserializer());
smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("","name"),Integer.class, null, new StringDeserializer());
并且还添加
@XmlRootElement(name = "Student",namespace="http://services.tuto.java.com/")
给学生班的
<?xml version="1.0" encoding="UTF-8"?>
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
<S:Body>
<ns2:getStudentsResponse xmlns:ns2="http://services.tuto.java.com/">
<student>
<matricule>1236</matricule>
<name>student1</name>
</student>
<student>
<matricule>5678</matricule>
<name>student2</name>
</student>
</ns2:getStudentsResponse>
</S:Body>
</S:Envelope>
轴客户端:
public class AxisClient
{
public static void main(String[] args) throws Exception
{
String endPoint = "http://localhost:8080/StudentServiceImplService/StudentServiceImpl";
Service service2 = new Service();
Call call2 = (Call) service2.createCall();
call2.setTargetEndpointAddress(new java.net.URL(endPoint));
call2.setOperationName(new QName("http://services.tuto.java.com/","getStudents"));
call2.setReturnType(new QName("","student"), Student.class);
call2.setReturnType(new QName("", "student"));
call2.registerTypeMapping(Student.class, new QName("", "student"), null,new BeanDeserializerFactory(Student.class, new QName("", "student")));
List<Student> students = (List<Student>) call2.invoke(new Object[0]);
for (Student student : students)
{
System.out.println(student);
}
}
}
给所有学生:
Student [matricule=1236, name=student1] Student [matricule=5678, name=student2]
axis2客户端:
public static void main(String[] args) throws Exception
{
String endPoint = "http://localhost:8080/StudentServiceImplService/StudentServiceImpl";
ServiceClient sc = new ServiceClient();
Options opts = new Options();
opts.setTo(new EndpointReference("http://localhost:8080/StudentServiceImplService/StudentServiceImpl"));
sc.setOptions(opts);
OMFactory fac = OMAbstractFactory.getOMFactory();
OMNamespace omNs = fac.createOMNamespace("http://services.tuto.java.com/","ns1");
OMElement method = fac.createOMElement("getStudents", omNs);
OMElement res = sc.sendReceive(method);
System.out.println(res);
Iterator<OMElement> it = res.getChildElements();
while(it.hasNext())
{
System.out.println(it.next());
}
}
给予
<ns2:getStudentsResponse xmlns:ns2="http://services.tuto.java.com/"><student><matricule>1236</matricule><name>student1</name></student><student><matricule>5678</matricule><name>student2</name></student></ns2:getStudentsResponse> <student><matricule>1236</matricule><name>student1</name></student> <student><matricule>5678</matricule><name>student2</name></student>
但我不知道如何反序列化这些元素.
我试过了
Student student = (Student) BeanUtil.deserialize(Student.class,res,new DefaultObjectSupplier(),null);
但是给了我
Student [matricule=null, name=null]
我能怎么做 ?
留下问题:
>不知道如何对轴做同样的事–OK见之前 – /轴2>’resp'(肥皂客户端)仅包含第一个学生
