我有一个关于泛型类序列化的问题. 因为我想为我的所有Configuration(它被序列化为XML)使用泛型类,所以我编写了以下类: Imports System.XmlImports System.Xml.SerializationImports System.IOImports System.R
因为我想为我的所有Configuration(它被序列化为XML)使用泛型类,所以我编写了以下类:
Imports System.Xml Imports System.Xml.Serialization Imports System.IO Imports System.Reflection Imports System.Reflection.Assembly <Serializable()> _ Public Class GenericConfig(Of T) Public Sub WriteToFile(ByVal FileName As String) ConfigVersion = ProgrammVersion.ToString Dim XmlFile As FileStream = New FileStream(FileName, FileMode.Create) Dim serialize As XmlSerializer = New XmlSerializer(GetType(GenericConfig(Of T)), New Type() {GetType(GenericConfig(Of T))}) serialize.Serialize(XmlFile, Me) XmlFile.Close() End Sub Public Shared Function ReadFromFile(ByVal FileName As String) As GenericConfig(Of T) Dim XmlFile As FileStream = New FileStream(FileName, FileMode.Open) Dim serialize As XmlSerializer = New XmlSerializer(GetType(GenericConfig(Of T))) ReadFromFile = serialize.Deserialize(XmlFile) XmlFile.Close() Return ReadFromFile End Function Public Shared ReadOnly Property ConfigFileName() As String Get Return GetExecutingAssembly.Location.Substring(0, GetExecutingAssembly.Location.Length - 4) & ".Config.xml" End Get End Property End Class Public Class ToolConfig Inherits GenericConfig(Of ToolConfig) Public Property Key1 As String = "Value 1" End Class
我遇到的问题是我无法序列化它,因为行中出现以下错误
serialize.Serialize(XmlFile, Me)
{“不期望GenericConfigClass.ToolConfig类型.使用XmlInclude或SoapInclude属性指定静态未知的类型.”}
如果你在派生类上使用XMLSerializer,我已经google搜索并找到了很多与该错误相关的文章.我不是在这里做的.我在泛型类上使用它.
除了在这里创建像这个伙伴这样的XML帮助器类之外,还有其他方法:
http://www.codeproject.com/Articles/35925/Generic-XML-Serialization-Methods
谢谢,
沃尔夫冈
更新:
这就是我所说的(简短例子)
Imports System.IO Public Class frmMain Dim Config As ToolConfig Private Sub btnConfigInit_Click(sender As Object, e As EventArgs) Handles btnConfigInit.Click '----------------- read config file ----------------- If File.Exists(ToolConfig.ConfigFileName) Then Config = ToolConfig.ReadFromFile(ToolConfig.ConfigFileName) Else Config = New ToolConfig End If Config.WriteToFile(ToolConfig.ConfigFileName) MsgBox(Config.Key1) End Sub End Class是的,您正在使用派生类:ToolConfig.通过XmlInclude让它知道,你应该没问题:
添加< XmlInclude(GetType(ToolConfig))>到GenericConfig.
另一个解决方案应该是在创建XmlSerializer实例时简单地使用Me.GetType()而不是GetType(GenericConfig(Of T)):
Dim serialize As XmlSerializer = New XmlSerializer(Me.GetType())
为了能够成功反序列化,您必须使共享的ReadFromFile方法成为实例方法或使其成为通用方法.
如果要保持共享的反序列化方法,可以这样做:
Public Class GenericConfig ' <- No (Of T) here! But in the line below. Public Shared Function ReadFromFile(Of T)(ByVal FileName As String) As T Dim XmlFile As FileStream = New FileStream(FileName, FileMode.Open) Dim serialize As XmlSerializer = New XmlSerializer(GetType(T)) ReadFromFile = serialize.Deserialize(XmlFile) XmlFile.Close() Return ReadFromFile End Function End Class
用法:
GenericConfig.ReadFromFile(Of ToolConfig)(filename)