我确信这已经完成了一百次,但我希望有一个非常简单的方法来实现这一点.我想把单词改成int. 像下面的例子 One = 1Two = 2Three = 3 所以基本上如果我有字符串“One”它会转换为1,即使我可以
像下面的例子
One = 1 Two = 2 Three = 3
所以基本上如果我有字符串“One”它会转换为1,即使我可以返回一个字符串“1”我可以转换它.
这样做是为了好玩……可能有许多边缘情况会失败……private static Dictionary<string,long> numberTable= new Dictionary<string,long> {{"zero",0},{"one",1},{"two",2},{"three",3},{"four",4}, {"five",5},{"six",6},{"seven",7},{"eight",8},{"nine",9}, {"ten",10},{"eleven",11},{"twelve",12},{"thirteen",13}, {"fourteen",14},{"fifteen",15},{"sixteen",16}, {"seventeen",17},{"eighteen",18},{"nineteen",19},{"twenty",20}, {"thirty",30},{"forty",40},{"fifty",50},{"sixty",60}, {"seventy",70},{"eighty",80},{"ninety",90},{"hundred",100}, {"thousand",1000},{"million",1000000},{"billion",1000000000}, {"trillion",1000000000000},{"quadrillion",1000000000000000}, {"quintillion",1000000000000000000}}; public static long ToLong(string numberString) { var numbers = Regex.Matches(numberString, @"\w+").Cast<Match>() .Select(m => m.Value.ToLowerInvariant()) .Where(v => numberTable.ContainsKey(v)) .Select(v => numberTable[v]); long acc = 0,total = 0L; foreach(var n in numbers) { if(n >= 1000) { total += (acc * n); acc = 0; } else if(n >= 100){ acc *= n; } else acc += n; } return (total + acc) * ( numberString.StartsWith("minus", StringComparison.InvariantCultureIgnoreCase) ? -1 : 1); }