c# – 从List返回较小的向量

var positions = new List<Vector3>();

positions.Add(new Vector3(135, 125, 13));
positions.Add(new Vector3(55, 12, 13));
positions.Add(new Vector3(1353, 346, 13));
positions.Add(new Vector3(1442, 979, 134));

private Vector3 SmallerPosition(List<Vector3> positions)
{
    positions.Sort();
    return positions[0];
}

Debug.Log(SmallerPosition(positions));

但我知道这是不可能的,所以,我怎样才能做到这一点？

positions.OrderBy(v => v.sqrMagnitude).First();