Unity实现已知落点和速度自动计算发射角度

本文实例为大家分享了Unity已知落点和速度自动计算发射角度的具体代码，供大家参考，具体内容如下

在发射物已知落点和速度的情况下如果刚体应用重力，不容易算出发射角度，以下为计算过程

/// <summary>
/// 挂载到发射器上即可
/// </summary>
public class Rotate : MonoBehaviour
{
 public GameObject prefab; //发射物
 public float speed;   //发射物速度
 public bool 抛射 = false; //抛射：仰角 > 45°，否：仰角 < 45°
 Ray RayMouse;
 Vector3 direction;
 Quaternion rotation;
 
 void Update()
 {
  if (Input.GetMouseButtonDown(0))
  {
   GameObject go = Instantiate(prefab, transform.position, transform.rotation);
   go.AddComponent<Rigidbody>().velocity = go.transform.forward * speed;
  }

  RaycastHit hit;
  RayMouse = Camera.main.ScreenPointToRay(Input.mousePosition);
  if (Physics.Raycast(RayMouse.origin, RayMouse.direction, out hit, Mathf.Infinity))
  {
   RotateToMouseDirection(gameObject, hit.point);
  }
 }

 /// <summary>
 /// 执行整体旋转
 /// </summary>
 /// <param name="obj">旋转的物体（自身）</param>
 /// <param name="destination">目标点（鼠标指向）</param>
 void RotateToMouseDirection(GameObject obj, Vector3 destination)
 {
  direction = destination - obj.transform.position;
  rotation = Quaternion.LookRotation(direction);

  Vector3 finalAngle = rotation.eulerAngles;
  float targetAng = Angle(destination);
  finalAngle = new Vector3(-targetAng, finalAngle.y, finalAngle.z);//注意正负

  obj.transform.localRotation = Quaternion.Euler(finalAngle);
 }

 /// <summary>
 /// 自动计算x欧拉角，即仰角
 /// </summary>
 /// <param name="target">目标点坐标</param>
 /// <returns></returns>
 float Angle(Vector3 target)
 {
  float angleX;
  float distX = Vector2.Distance(new Vector2(target.x, target.z), new Vector2(transform.position.x, transform.position.z));
  float distY = target.y - transform.position.y;
  float posBase = (Physics.gravity.y * Mathf.Pow(distX, 2.0f)) / (2.0f * Mathf.Pow(speed, 2.0f));
  float posX = distX / posBase;
  float posY = (Mathf.Pow(posX, 2.0f) / 4.0f) - ((posBase - distY) / posBase);
  if (posY >= 0.0f)
  {
   if (抛射) //字段
    angleX = Mathf.Rad2Deg * Mathf.Atan(-posX / 2.0f + Mathf.Pow(posY, 0.5f));
   else
    angleX = Mathf.Rad2Deg * Mathf.Atan(-posX / 2.0f - Mathf.Pow(posY, 0.5f));
  }
  else
  {
   angleX = 45.0f;
  }
  return angleX;
 }
}

实际效果

抛射效果

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持易盾网络。