opencv提取轮廓大于某个阈值的图像

本文实例为大家分享了opencv提取轮廓大于某个阈值的图像，供大家参考，具体内容如下

#include "stdafx.h"
#include "cv.h"
#include "highgui.h"
#include "stdio.h"
#include"core/core.hpp"
#include "opencv2/highgui/highgui.hpp"
#include "opencv2/core/core.hpp"
#include "opencv2/imgproc/imgproc.hpp"
 
 
#include <iostream>
 
 
using namespace cv;
using namespace std;
int main(int argc, char** argv)
{
 
const char* inputImage = "d:/3.jpg"; 
 Mat img; 
 int threshval =100; 
 img = imread(inputImage,0); 
 if (img.empty()) 
 { 
 cout << "Could not read input image file: " << inputImage << endl; 
 return -1; 
 } 
  
 img = img >110; 
 namedWindow("Img", 1); 
 imshow("Img", img); 
 vector<vector<Point> > contours; 
 vector<Vec4i>hierarchy; 
 
 vector<Point> contour;
 Mat dst = Mat::zeros(img.rows, img.cols, CV_8UC3); 
 findContours(img, contours,hierarchy, CV_RETR_CCOMP, CV_CHAIN_APPROX_SIMPLE); 
 
 int m=contours.size();//得到轮廓的数量
 int n=0;
 for (int i =0;i<m;++i)
 {
 n=contours[i].size();
 for (int j =0;j<n;++j)
 {
  contour.push_back(contours[i][j]);//读取每个轮廓的点
 }
 double area = contourArea(contour); //取得轮廓面积
 
 if (area>10)//只画出轮廓大于10的点
 {
 Scalar color( (rand()&255), (rand()&255), (rand()&255) ); 
 
  drawContours( dst, contours, i, color, 1, 8, hierarchy ); 
 }
 contour.clear();
 
 }
 
 namedWindow("src", 1); 
 imshow( "src", dst ); 
 
  waitKey();
  return 0;
}

左边为二值化的图像

右边为提取面积大于10的轮廓的图像

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持自由互联。