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如何实现java8 list按照元素的某个字段去重

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list 按照元素的某个字段去重 @Data@AllArgsConstructor@NoArgsConstructorpublic class Student {private Integer age;private String name;} 测试数据 ListStudent studentList = Lists.newArrayList();studentList.add(new Student(28, "ri

list 按照元素的某个字段去重

@Data
@AllArgsConstructor
@NoArgsConstructor
public class Student {
private Integer age;
private String name;
}

测试数据

List<Student> studentList = Lists.newArrayList();
studentList.add(new Student(28, "river"));
studentList.add(new Student(12, "lucy"));
studentList.add(new Student(33, "frank"));
studentList.add(new Student(33, "lucy"));

java8 通过tree set 去重

List<Student> studentDistinctList = studentList.stream()
.collect(Collectors.collectingAndThen
(Collectors.toCollection(() ->
new TreeSet<>(Comparator.comparing(t -> t.getName()))),
ArrayList::new
)
);
System.out.println(new Gson().toJson(studentDistinctList));

扩展distinct 方法去重

List<Student> studentDistinct2List = studentList.stream().filter(StreamUtil.distinctByKey(t->t.getName()))
.collect(Collectors.toList());
System.out.println(new Gson().toJson(studentDistinct2List));

工具类

public class StreamUtil {
/**
* https://stackoverflow.com/questions/23699371/java-8-distinct-by-property
* @param keyExtractor
* @param <T>
* @return
*/
public static <T> Predicate<T> distinctByKey(Function<? super T, ?> keyExtractor) {
Set<Object> seen = ConcurrentHashMap.newKeySet();
return t -> seen.add(keyExtractor.apply(t));
}
}

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