原文:https://www . geesforgeks . org/通过从给定字符串的十六进制表示中移除字符来修改数组/
给定一个大小为 N 的数组arr【】和一个字符串 S ，任务是通过从 S 中存在的十六进制表示中移除所有字符，然后将等效的十进制元素替换回数组来修改给定数组。
示例:
输入: arr[] = {74，91，31，122}，S = "1AB"输出: {4，5，15，7}解释:T8】74->(4A)16->(4)16->491->(5B)16->(5)116
输入: arr[] = {1450，1716，284，843}，S = "ABFE3"输出: {5，100，284，4}
方法:按照以下步骤解决问题:
- 穿越阵T2【arr】:
- 将每个数组元素转换为其等价的十六进制值。
- 从字符串 s 中存在的十六进制数中删除字符
- 将修改后的十六进制数转换回十进制表示。
- 用它替换数组元素。
- 打印修改后的数组。
下面是上述方法的实现:
C++
// C++ program for the above approach#include using namespace std;// Function to convert a decimal number// to its equivalent hexadecimal numberstring decHex(int n){ char alpha[] = { 'A', 'B', 'C', 'D', 'E', 'F' }; string ans; while (n > 0) { if (n % 16 <10) { ans += to_string(n % 16); } else { ans += alpha[n % 16 - 10]; } n /= 16; } reverse(ans.begin(), ans.end()); return ans;}// Function to convert hexadecimal number// to its equavalent decimal numberint hexDec(string convertedHex){ // Stores characters with their // respective hexadecimal values char mp[] = { 10, 11, 12, 13, 14, 15 }; // Stores answer int ans = 0; int pos = 0; // Traverse the string reverse(convertedHex.begin(), convertedHex.end()); for (char ch : convertedHex) { // If digit if (isdigit(ch)) { ans += ((int)pow(16, pos)) * (ch - '0'); } // If character else { ans += ((int)pow(16, pos)) * mp[ch - 'A']; } pos += 1; } // Return the answer return ans;}// Function to move all the// alphabets to frontstring removeChars(string hexaVal, string S){ set setk; for (char ch : S) { setk.insert(ch); } string ans = ""; for (char ch : hexaVal) { if (setk.find(ch) != setk.end()) { continue; } ans += ch; } return ans;}// Function to modify each array// element by removing characters// from their hexadecimal representation// which are present in a given stringvoid convertArr(int arr[], int N, string S){ // Traverse the array for (int i = 0; i // java program for the above approachimport java.io.*;import java.lang.*;import java.util.*;class GFG { // Function to convert a decimal number // to its equivalent hexadecimal number static String decHex(int n) { char alpha[] = { 'A', 'B', 'C', 'D', 'E', 'F' }; StringBuilder ans = new StringBuilder(""); while (n > 0) { if (n % 16 <10) { ans.append(Integer.toString(n % 16)); } else { ans.append(alpha[n % 16 - 10]); } n /= 16; } ans = ans.reverse(); return ans.toString(); } // Function to convert hexadecimal number // to its equavalent decimal number static int hexDec(String convertedHex) { // Stores characters with their // respective hexadecimal values char mp[] = { 10, 11, 12, 13, 14, 15 }; // Stores answer int ans = 0; int pos = 0; // Traverse the string StringBuilder s = new StringBuilder(convertedHex); cOnvertedHex= s.reverse().toString(); for (char ch : convertedHex.toCharArray()) { // If digit if (Character.isDigit(ch)) { ans += ((int)Math.pow(16, pos)) * (ch - '0'); } // If character else { ans += ((int)Math.pow(16, pos)) * mp[ch - 'A']; } pos += 1; } // Return the answer return ans; } // Function to move all the // alphabets to front static String removeChars(String hexaVal, String S) { HashSet setk = new HashSet(); for (char ch : S.toCharArray()) { setk.add(ch); } String ans = ""; for (char ch : hexaVal.toCharArray()) { if (setk.contains(ch)) { continue; } ans += ch; } return ans; } // Function to modify each array // element by removing characters // from their hexadecimal representation // which are present in a given string static void convertArr(int arr[], String S) { // Traverse the array for (int i = 0; i // Stores hexadecimal value String hexaVal = decHex(arr[i]); // Remove the characters from hexadecimal // representation present in string S String cOnvertedHex= removeChars(hexaVal, S); // Stores decimal value int decVal = hexDec(convertedHex); // Replace array element arr[i] = decVal; } // Print the modified array for (int val : arr) { System.out.print(val + " "); } } // Driver Code public static void main(String[] args) { // Given array int arr[] = { 74, 91, 31, 122 }; // Given string String S = "1AB"; // Function call to modify // array by given operations convertArr(arr, S); }}// This code is contributed by Kingash. # Python3 program for the above approach# Function to convert a decimal number# to its equivalent hexadecimal numberdef decHex(n): alpha = ['A', 'B', 'C', 'D', 'E', 'F'] ans = '' while n: if n % 16 <10: ans += str(n % 16) else: ans += alpha[n % 16 - 10] n //= 16 ans = ans[::-1] return ans# Function to convert hexadecimal number# to its equavalent decimal numberdef hexDec(convertedHex): # Stores characters with their # respective hexadecimal values mp = {"A": 10, "B": 11, "C": 12, "D": 13, "E": 14, "F": 15} # Stores answer ans = 0 pos = 0 # Traverse the string for i in convertedHex[::-1]: # If digit if i.isdigit(): ans += (16**pos)*int(i) # If character else: ans += (16**pos)*mp[i] pos += 1 # Return the answer return ans# Function to move all the# alphabets to frontdef removeChars(hexaVal, S): setk = set() for i in S: setk.add(i) ans = '' for i in hexaVal: if i in setk: continue ans += i return ans# Function to modify each array# element by removing characters# from their hexadecimal representation# which are present in a given stringdef convertArr(arr, S): # Traverse the array for i in range(len(arr)): # Stores hexadecimal value hexaVal = decHex(arr[i]) # Remove the characters from hexadecimal # representation present in string S cOnvertedHex= removeChars(hexaVal, S) # Stores decimal value decVal = hexDec(convertedHex) # Replace array element arr[i] = decVal # Print the modified array print(arr)# Driver Code# Given arrayarr = [74, 91, 31, 122]# Given stringS = "1AB"# Function call to modify# array by given operationsconvertArr(arr, S) Output: [4, 5, 15, 7] 时间复杂度:O(N * | S |)T5辅助空间:** O(|S|)Python 3