C++实现从数组中同时取出最大最小元素算法示例

本文实例讲述了C++实现从数组中同时取出最大最小元素的方法。分享给大家供大家参考，具体如下：

算法思想：先相邻两个两个比较，较大的放入数组max[],较小的放入数组min[],然后从max[]数组求出最大，min[]数组求出最小即可。

比较n+[(n+1)/2] =1.5n次

#include <iostream>
#define n 11
#define m ((n+1)/2)
using namespace std;
void main(void)
{
  int num[] = {11,2,3,4,6,5,7,8,9,10,20};
  //int n = sizeof(num)/sizeof(num[0]);
  //int m = (n+1)/2;
  int max[m] , min[m];
  int k = 0, j = 0;
  if(n/2 != 0) max[m-1] = min[m-1] = num[n-1];
  for (int i=0; i < n-1; i = i+2)
  {
    if (num[i] >= num[i+1])
    {
      max[j++] = num[i];
      min[k++] = num[i+1];
    }
    else
    {
      max[j++] = num[i+1];
      min[k++] = num[i];
    }
  }
  for( i=0; i< m; i++)
  {
    cout << "max[" << i << "] = " << max[i] << "\t";
    cout << "min[" << i << "] = " << min[i] <<endl;
  }
  int MAX = max[0];
  int MIN = min[0];
  for ( j = 1; j < m; j++)
  {
    if (max[j] > MAX) MAX = max[j];
    if (min[j] < MIN) MIN = min[j];
  }
  cout << "MAX = " << MAX << ", MIN = " << MIN <<endl;
}

希望本文所述对大家C++程序设计有所帮助。