Given an array A of strings made only from lowercase letters, return a list of all characters that show up in all strings within the list(including duplicates).For example, if a character occurs 3 timesin all strings but not 4 times, you ne
Given an array
A
of strings made only from lowercase letters, return a list of all characters that show up in all strings within the list (including duplicates). For example, if a character occurs 3 times in all strings but not 4 times, you need to include that character three times in the final answer.You may return the answer in any order.
Example 1:
Input: ["bella","label","roller"] Output: ["e","l","l"]
Example 2:
Input: ["cool","lock","cook"] Output: ["c","o"]
Note:
1 <= A.length <= 100
1 <= A[i].length <= 100
A[i][j]
is a lowercase letter
Approach #1: Array. [Java]
class Solution { public List<String> commonChars(String[] A) { List<String> ret = new ArrayList<>(); int[] count = new int[26]; Arrays.fill(count, Integer.MAX_VALUE); for (String a : A) { int[] cnt = new int[26]; for (char c : a.toCharArray()) ++cnt[c-‘a‘]; for (int i = 0; i < 26; ++i) count[i] = Math.min(count[i], cnt[i]); } for (int i = 0; i < 26; ++i) while (count[i]-- > 0) ret.add(""+(char)(i + ‘a‘)); return ret; } }
Reference:
https://leetcode.com/problems/find-common-characters/discuss/247558/Java-12-liner-count-and-look-for-minimum.