需要帮助显示每30分钟的时间间隔,假设当前时间是上午11:45 时间间隔应为:中午12:00,下午12:30,下午01:00,下午01:30,下午02:00,下午02:30 ……晚上10:30. NSString *time = @"10.30 pm"; NSDate *date1; N
时间间隔应为:中午12:00,下午12:30,下午01:00,下午01:30,下午02:00,下午02:30 ……晚上10:30.
NSString *time = @"10.30 pm"; NSDate *date1; NSDate *date2; { NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; [formatter setDateFormat:@"hh.mm a"]; date1 = [formatter dateFromString:time]; date2 = [formatter dateFromString:[formatter stringFromDate:[NSDate date]]]; } NSTimeInterval interval = [date1 timeIntervalSinceDate: date2];//[date1 timeIntervalSince1970] - [date2 timeIntervalSince1970]; int hour = interval / 3600; int minute = (int)interval % 3600 / 60; NSLog(@"%@ %dh %dm", interval<0?@"-":@"+", ABS(hour), ABS(minute));
此代码返回当前时间与给定时间的差异,如何进一步处理.
你可以做点什么,NSString *startTime = @"02:00 AM"; NSString *endTime = @"11:00 AM"; NSDateFormatter *timeFormat = [[NSDateFormatter alloc] init]; [timeFormat setDateFormat:@"hh:mm a"]; NSDate* fromTime = [timeFormat dateFromString:startTime]; NSDate* toTime = [timeFormat dateFromString:endTime]; NSDate *dateByAddingThirtyMinute ; NSTimeInterval timeinterval = [toTime timeIntervalSinceDate:fromTime]; NSLog(@"time Int %f",timeinterval/3600); float numberOfIntervals = timeinterval/3600; NSLog(@"Start time %f",numberOfIntervals); for(int iCount = 0;iCount < numberOfIntervals*2 ;iCount ++) { dateByAddingThirtyMinute = [fromTime dateByAddingTimeInterval:1800]; fromTime = dateByAddingThirtyMinute; NSString *formattedDateString; NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; [dateFormatter setDateFormat:@"hh:mm a"]; formattedDateString = [dateFormatter stringFromDate:dateByAddingThirtyMinute]; NSLog(@"Time after 30 min %@",formattedDateString); }
在for循环中,我已经取了numberOfIntervals * 2,因为时间间隔是30分钟,所以60/30 = 2,你的datebyAddingThirtyMinute是1800,因为30分钟= 1800秒.如果你想要每10分钟一次,那么它应该是60/10 = 6,所以它应该是numberOfIntervals * 6.你的datebyAddingThirtyMinute应该是[fromTime dateByAddingTimeInterval:600];
希望这会有所帮助:)