ios – 如何在视图外点击时关闭模态表单？

我不知道如何在 Swift中实现以下功能：

我在我的iPad应用程序中显示模态表单弹出窗口.为了驳回这个观点,我添加了一个解除它的按钮.但我真正想要的是当你点击视图外面时它会被忽略.与popover几乎相同的行为.我尝试通过添加点击手势来实现这一点,使其成为一个弹出窗口,任何演示样式,没有任何作用.

有人可能这样做,以便你可以指出我正确的方向？

我必须在我的应用程序中显示一些像弹出窗口的屏幕,所以我已经创建了如下所示的基类：

class MyBasePopUp: UIViewController, UIGestureRecognizerDelegate {

var tap: UITapGestureRecognizer!
override func viewDidAppear(_ animated: Bool) {

    tap = UITapGestureRecognizer(target: self, action: #selector(onTap(sender:)))
    tap.numberOfTapsRequired = 1
    tap.numberOfTouchesRequired = 1
    tap.cancelsTouchesInView = false
    tap.delegate = self
    self.view.window?.addGestureRecognizer(tap)
}

internal func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldRecognizeSimultaneouslyWith otherGestureRecognizer: UIGestureRecognizer) -> Bool {
    return true
}

internal func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool {
    let location = touch.location(in: self.view)

    if self.view.point(inside: location, with: nil) {
        return false
    }
    else {
        return true
    }
}

@objc private func onTap(sender: UITapGestureRecognizer) {

    self.view.window?.removeGestureRecognizer(sender)
    self.dismiss(animated: true, completion: nil)
}

这只是为了解除弹出窗口,如果您有多个手势,请小心.