xml – 如何获取当前节点变量的父节点元素？

<xsl:template match="/">
            <xsl:call-template name="generateLinks">
        <xsl:with-param name="currentPageBranchVariable" select="//Item[@CurrentPageBranch='true']"></xsl:with-param>
      </xsl:call-template>

  </xsl:template>

和：

<xsl:template name="generateLinks">
    <xsl:param name="currentPageBranchVariable"></xsl:param>

    <xsl:value-of select="$currentPageBranchVariable/@FullName"/>

    // how to get the parent node of $currentPageBranchVariable?

  </xsl:template>

可以看出,$currentPageBranchVariable是包含Item节点的第二个模板的变量.

怎么可能从那里得到它的父元素？

我尝试了以下但没有奏效：

<xsl:value-of select="../$currentPageBranchVariable/@FullName"/>
<xsl:value-of select="parent::node()/$currentPageBranchVariable/@FullName"/>
<xsl:value-of select="parent($currentPageBranchVariable)/@FullName"/>

希望问题很清楚.

也许我想要做的是不可能的？

谢谢,

the $currentPageBranchVariable is a variable for the second template
which contains an Item node.

How would that be possible to get its parent element from there?

只需使用：

$currentPageBranchVariable/..

这将选择$currentPageBranchVariable中包含的所有节点(在这种情况下只有一个)的父节点(每个节点).