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kml – 用pyephem检索的卫星轨迹的可视化已关闭

来源:互联网 收集:自由互联 发布时间:2021-06-16
使用下面的代码,并使用pyephem和fastkml,我想从TLE中提取卫星的地面轨迹.代码如下: import numpy as npimport ephemimport datetime as dtfrom fastkml import kmlfrom shapely.geometry import Point, LineString, Polygonnam
使用下面的代码,并使用pyephem和fastkml,我想从TLE中提取卫星的地面轨迹.代码如下:

import numpy as np
import ephem
import datetime as dt
from fastkml import kml
from shapely.geometry import Point, LineString, Polygon

name = "ISS (ZARYA)"             
line1 = "1 25544U 98067A   16018.27038796  .00010095  00000-0  15715-3 0  9995"
line2 = "2 25544  51.6427  90.6544 0006335  30.9473  76.2262 15.54535921981506"

tle_rec = ephem.readtle(name, line1, line2)

start_dt = dt.datetime.today()
intervall = dt.timedelta(minutes=1)

timelist = []
for i in range(100):
    timelist.append(start_dt + i*intervall)

positions = []
for t in timelist:
    tle_rec.compute(t)
    positions.append((tle_rec.sublong,tle_rec.sublat,tle_rec.elevation))

k = kml.KML()
ns = '{http://www.opengis.net/kml/2.2}'
p = kml.Placemark(ns, 'Sattrack', 'Test', '100 Minute Track')
p.geometry =  LineString(positions)#, tesselate=1,altitudemode="absolute")
k.append(p)

with open("test.kml", 'w') as kmlfile:
    kmlfile.write(k.to_string())

遗憾的是,当我将kml加载到Google Earth时,该轨道如下所示:

这出错的想法?

你的地面轨道是一个环绕0°N(在赤道上)和0°E(格林威治以南,靠近几内亚湾)的位置.这表明您使用以弧度表示的角度,最多可以达到约6.2的值,并将它们传递给映射软件,将其读取为度数.

您应该首先尝试将它们转换为度数:

positions.append((tle_rec.sublong / ephem.degree,
                  tle_rec.sublat / ephem.degree,
                  tle_rec.elevation))
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