[[Prototype]]和原型在JavaScript中的关系

Note: ECMAScript defines an internal [[prototype]] property of the internal Object type. This property is not directly accessible with scripts, but it is the chain of objects referred to with the internal [[prototype]] property that is used in property accessor resolution; the object’s prototype chain. A public prototype property exists to allow the assignment, definition and manipulation of prototypes in association with the internal [[prototype]] property. The details of the relationship between to two are described in ECMA 262 (3rd edition) and are beyond the scope of this discussion.

两者之间关系的细节是什么？我已浏览过ECMA 262，所有我读过的东西就像：

The constructor’s associated prototype can be referenced by the program expression constructor.prototype,

Native ECMAScript objects have an internal property called [[Prototype]]. The value of this property is either null or an object and is used for implementing inheritance.

Every built-in function and every built-in constructor has the Function prototype object, which is the initial value of the expression Function.prototype

Every built-in prototype object has the Object prototype object, which is the initial value of the expression
Object.prototype (15.3.2.1), as the value of its internal [[Prototype]] property, except the Object
prototype object itself.

从这一切我收集的是[[Prototype]]属性相当于几乎任何对象的原型属性。我错了吗

每个对象都有一个隐藏的[[Prototype]]属性，用于继承。函数另外有一个公共原型属性，仅当该函数用作构造函数时才使用：当使用new构造对象时，新对象的[[Prototype]]属性设置为函数的原型属性，即用作构造函数。

例如。

function C() {}
C.prototype = P1;  
var obj = new C();  // obj.[[Prototype]] is now P1.

您可以使用Object.getPrototypeOf(< obj>)获取[[Prototype]]属性。 (此方法在ECMAScript 5中指定。较旧版本的JavaScript没有任何标准的阅读方式[[Prototype]])。

您通常可以通过构造函数获得原型，例如：

obj.constructor.prototype == Object.getPrototypeOf(obj)

但是并不总是如此，因为可以重新分配构造函数的prototype属性，而是在创建对象后无法重新分配对象的[[Prototype]]。所以如果你这样做：

C.prototype = P2;

然后

obj.constructor.prototype != Object.getPrototypeOf(obj)

因为C的原型现在是P2，而obj的[[Prototype]]仍然是P1。

请注意，它只是具有原型属性的函数。还要注意，函数的prototype属性与函数的[[Prototype]]属性不同！