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循环 – 用于在表中创建变量的Lua循环

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我在循环中有问题,Lua中的表 这是带变量knx的表(现在它是静态的) regTable = { { RegEddr=3027, count=2, regType="float", knx="1/1/1"}, { RegEddr=3029, count=2, regType="float", knx="1/1/2"}, { RegEddr=3031, count=2, regT
我在循环中有问题,Lua中的表
这是带变量knx的表(现在它是静态的)

regTable = {
      { RegEddr=3027, count=2, regType="float", knx="1/1/1"},
      { RegEddr=3029, count=2, regType="float", knx="1/1/2"},
      { RegEddr=3031, count=2, regType="float", knx="1/1/3"},
      { RegEddr=2999, count=2, regType="float", knx="1/1/4"},
      { RegEddr=3001, count=2, regType="float", knx="1/1/5"},
      { RegEddr=3003, count=2, regType="float", knx="1/1/6"},
      { RegEddr=3109, count=2, regType="float", knx="1/1/7"},
      { RegEddr=3083, count=2, regType="float", knx="1/1/8"},
      { RegEddr=3059, count=2, regType="float", knx="1/1/9"},
      { RegEddr=3203, count=4, regType="int64", knx="1/1/10"},
    }

    function readRegisters()

    for idx, register in pairs(regTable) do
      if register.regType=="int" then
        valueInt = mb:readregisters(register.RegEddr)
        grp.write(register.knx, valueInt)




            elseif register.regType=="float" then
                     value1, value2 = mb:readregisters(register.RegEddr,register.count)

            if value1 then
                     valueFloat = bit.lshift(value1, 16) + value2
                     valueFloat = lmcore.inttohex(valueFloat, 4)
                     valueFloat = knxdatatype.decode(valueFloat, dt.float32)
            grp.write(register.knx, valueFloat)
               end

           elseif register.regType=="int64" then
          valueInt1, valueInt2, valueInt3, valueInt4 = mb:readregisters(register.RegEddr,register.count)
          if valueInt4 then
            valueInt64 = valueInt4
                log(valueInt64)
                grp.write(register.knx, valueInt64)
            end




       end

      end     --end for

    end --end function

从另一个脚本我调用函数readRegisters()
所以我有地址列表,但我不知道用户需要多少个地址.如果是10或100.这就是为什么拥有地址列表而不是最佳状态的原因,只有1步的动态列表

1/1/1
1/1/2
...
1/1/255

有可能帮助我如何动态地将地址变量knx添加到此表中?

您需要一个寄存器分配器功​​能,它考虑了最后一个寄存器的地址和大小.此分配器将在您请求时动态创建新寄存器.

local startAddr = 3000
local sizes = {float = 2, int = 2, int64 = 4}
local registers = {}

local function allocRegister(type)
  if sizes[type] == nil then
    error'invalid register type'
  end

  local n = #registers
  local addr

  if n == 0 then -- If this is the first register, use the starting address.
    addr = startAddr
  else -- Determine the next starting address based on the last register's address & size.
    addr = registers[n].addr + registers[n].count
  end

  table.insert(registers, { addr = addr, count = sizes[type], type = type, knx = '1/1/' .. n + 1 })
end

-- Example usage:
allocRegister'float'
allocRegister'int64'
allocRegister'int'
-- Resulting table:
{
  { addr = 3000, count = 2, knx = "1/1/1", type = "float" },
  { addr = 3002, count = 4, knx = "1/1/2", type = "int64" },
  { addr = 3006, count = 2, knx = "1/1/3", type = "int" }
}

您也可以在循环中使用此函数.以下循环将创建一个非常类似于您的问题中的寄存器表.

for i=1, 9 do allocRegister'float' end
allocRegister'int64'

编辑:以下代码应足以说明如何解决您的问题.

local sizes = {float = 2, int = 2, int64 = 4}
local registers = {}
local usedSpace = {}

local function allocRegisters(t)
  for i=1, #t do
    local addr, size = t[i].addr, sizes[t[i].type]

    if size == nil then
      error('invalid register type: ' .. t[i].type)
    end

    -- Check if there's free space for this register.
    for j=addr, addr+size-1 do
      if usedSpace[j] then
        error('address already in use: ' .. addr)
      end
    end

    -- Mark the space for this register as used.
    for j=addr, addr+size-1 do
      usedSpace[j] = true
    end

    -- Copy the register into the registers table, setting knx by using the length of the table.
    table.insert(registers, { addr = addr, count = size, type = t[i].type, knx = '1/1/' .. #registers + 1})
  end
end

-- Example usage:
allocRegisters {
  { addr = 3000, type = 'float' },
  { addr = 3003, type = 'int' },
  { addr = 3009, type = 'int64' }
}
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