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lua – 逐行读取文件到数组中

来源:互联网 收集:自由互联 发布时间:2021-06-23
对不起,我还在学习lua.你可以纠正我,为什么文件中的数据不会逐行读取? 这是我在文件points.txt中的示例数据: lexxo:30:1rey:40:2lion:40:2prince:50:3royal:50:3 所以当我从上面得到的是2d阵列(表
对不起,我还在学习lua.你可以纠正我,为什么文件中的数据不会逐行读取?

这是我在文件points.txt中的示例数据:

lexxo:30:1
rey:40:2
lion:40:2
prince:50:3
royal:50:3

所以当我从上面得到的是2d阵列(表)

player = {{(name),(points),(which var point earned on index)},
          {(...),(...),(...)}};

所以问题是,当我尝试循环打印文件中的所有数据.它只打印最新的一行.所以我想要打印所有这些

line_points =  {}
player_data = {{}}

local rfile = io.open("points.txt", "r")
for line in rfile:lines() do
    playername, playerpoint, playeridpoint = line:match("^(.-):(%d+):(%d+)$")
    player_data = {{playername, playerpoint, playeridpoint}}
    line_points[#line_points + 1] = player_data
end

for i = 1, #player_data do
    player_checkname = player_data[i][1] -- Get Player Name From Array for checking further
    player_checkpnt = player_data[i][3] -- Get Player ID Point From Array for checking further
    print(i..". Name: "..player_data[i][1].." Point: ".. player_data[i][2] .. " ID: " .. player_data[i][3]);
end
player_data总是有索引1,因为你没有向它添加项目,你将它们添加到line_points,其中#line_points是5,所以请改用它.

那是你想要的吗?

line_points =  {}
player_data = {{}} --I think you can delete it at all...
--Because it is rewriting each time.

local rfile = io.open("points.txt", "r")
for line in rfile:lines() do
    playername, playerpoint, playeridpoint = line:match("^(.-):(%d+):(%d+)$")
    player_data = {playername, playerpoint, playeridpoint}
    --I also remover double table here ^^^^^^^^^^^^^^^^^^^
    line_points[#line_points + 1] = player_data
end
--Here i checked counts
--print('#pd='..#player_data)
--print('#lp='..#line_points)
--After it i decided to use line_points instead of player_data
for i = 1, #line_points do
    player_checkname = line_points[i][1] -- Get Player Name From Array for checking further
    player_checkpnt = line_points[i][3] -- Get Player ID Point From Array for checking further
    print(i..". Name: "..line_points[i][1].." Point: ".. line_points[i][2] .. " ID: " .. line_points[i][3]);
end

输出:

1. Name: lexxo Point: 30 ID: 1
2. Name: rey Point: 40 ID: 2
3. Name: lion Point: 40 ID: 2
4. Name: prince Point: 50 ID: 3
5. Name: royal Point: 50 ID: 3

更新:

在第一个循环中将player_data assignemnt更改为单个表后,它的计数总是为3.

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