有没有模式的Lua string.find

function find_without_pattern(s1,s2)
    for i =1,#s1-#s2+1 do
        local t = string.sub(s1,i,#s2+i-1)
        if t == s2 then
            return i,i+#s2-1
        end
    end
end

例如：

string.find("he#.*o", "e#.*o", 1, true)

会给你正确的结果.

引用Lua手册页：

string.find (s, pattern [, init [, plain]])

A value of true as a fourth, optional argument plain turns off the pattern matching facilities, so the function does a plain “find substring” operation, with no characters in pattern being considered magic. Note that if plain is given, then init must be given as well.