到目前为止,我有以下内容: local socket = require "socket.http"client,r,c,h = socket.request{url = "http://example.com/", proxy="my proxy and port here"}for i,v in pairs( c ) do print( i, v )end 这给了我一个如下输出:
local socket = require "socket.http" client,r,c,h = socket.request{url = "http://example.com/", proxy="<my proxy and port here>"} for i,v in pairs( c ) do print( i, v ) end
这给了我一个如下输出:
connection close content-type text/html; charset=UTF-8 location http://www.iana.org/domains/example/ vary Accept-Encoding date Tue, 24 Apr 2012 21:43:19 GMT last-modified Wed, 09 Feb 2011 17:13:15 GMT transfer-encoding chunked server Apache/2.2.3 (CentOS)
这意味着连接建立得非常完美.现在,我想使用这个socket.http获取我的url的标题.我搜索了之前的SO问题和luasocket’s http documentation.但是,我仍然不知道如何在变量中获取/存储整个/部分页面并使用它做一些事情.
请帮忙.
您正在使用http.request()的“通用”形式,这需要通过LTN12接收器存储主体.它并不像听起来那么复杂,试试这段代码:local socket = require "socket.http" local ltn12 = require "ltn12"; -- LTN12 lib provided by LuaSocket -- This table will store the body (possibly in multiple chunks): local result_table = {}; client,r,c,h = socket.request{ url = "http://example.com/", sink = ltn12.sink.table(result_table), proxy="<my proxy and port here>" } -- Join the chunks together into a string: local result = table.concat(result_table); -- Hacky solution to extract the title: local title = result:match("<[Tt][Ii][Tt][Ll][Ee]>([^<]*)<"); print(title);
如果您的代理在整个应用程序中保持不变,那么更直接的解决方案是使用http.request()的简单形式,并通过http.PROXY指定代理:
local http = require "socket.http" http.PROXY="<my proxy and port here>" local result = http.request("http://www.youtube.com/watch?v=_eT40eV7OiI") local title = result:match("<[Tt][Ii][Tt][Ll][Ee]>([^<]*)<"); print(title);
输出:
Flanders and Swann - A song of the weather - YouTube