Lua – 获取indexOf字符串

我在Lua中遇到问题,检查字符串值是否未在另一个字符串中显示.

这就是我在Javascript中可能会这样做的方式：

'my string'.indexOf('no-cache') === -1 // true

但在Lua我试图使用字符串模块,这给了我意想不到的响应：

string.find('my string', 'no-cache') -- nil, that's fine but..
string.find('no-cache', 'no-cache') -- nil.. that's weird
string.find('no-cache', 'no') -- 1, 2 here it's right.. strange..

正如已经提到的那样, – 是模式元字符, specifically：

• a single character class followed by ‘-‘, which also matches 0 or more repetitions of characters in the class. Unlike ‘*’, these repetition items will always match the shortest possible sequence;

您可能对string.find的普通选项感兴趣.这将避免将来转义任何其他内容.

string.find('no-cache', 'no-cache', 1, true)