我试图在TEnumerator中公开构建私有静态数组. Delphi本身允许直接枚举静态数组(见下文),所以我怀疑Delphi在后台为静态数组创建一个枚举器,我希望我能够在GetEnumerator方法中创建和公开相同
Delphi本身允许直接枚举静态数组(见下文),所以我怀疑Delphi在后台为静态数组创建一个枚举器,我希望我能够在GetEnumerator方法中创建和公开相同的枚举器.
(我使用的是Delphi XE2).
program Project6;
{$APPTYPE CONSOLE}
{$R *.res}
uses
System.SysUtils,
System.Generics.Collections;
type
TMyEnum = (meA, meB);
TMyClass = class
private
FItems: array[TMyEnum] of Integer;
protected
public
function GetEnumerator: TEnumerator<Integer>;
end;
{ TMyClass }
function TMyClass.GetEnumerator: TEnumerator<Integer>;
begin
// What is the simplies way of creating this enumerator?
end;
var
myObj: TMyClass;
i: Integer;
begin
myObj := TMyClass.Create;
try
// This works but only in the same unit
for i in myObj.FItems do
WriteLn(i);
for i in myObj do
WriteLn(i);
except
on E: Exception do
Writeln(E.ClassName, ': ', E.Message);
end;
ReadLn;
end.
请注意,我可以编写如下的自定义模拟器.但我试图避免这种情况并暴露内置的.
TStaticArrayEnumerator<T> = class(TEnumerator<T>)
private
FCurrent: Pointer;
FElementAfterLast: Pointer;
protected
function DoGetCurrent: T; override;
function DoMoveNext: Boolean; override;
public
constructor Create(aArray: Pointer; aCount: Integer);
end;
{ TStaticArrayEnumerator<T> }
constructor TStaticArrayEnumerator<T>.Create(aArray: Pointer; aCount: Integer);
begin
// need to point Current before the first element (see comment in DoMoveNext)
FCurrent := Pointer(NativeInt(aArray) - SizeOf(T));
FElementSize := aElementSize;
FElementAfterLast := Pointer(NativeInt(aArray) + aCount * SizeOf(T))
end;
function TStaticArrayEnumerator<T>.DoGetCurrent: T;
begin
Result := T(FCurrent^);
end;
function TStaticArrayEnumerator<T>.DoMoveNext: Boolean;
begin
// This method gets called before DoGetCurrent gets called the first time
FCurrent := Pointer(NativeInt(FCurrent) + SizeOf(T));
Result := not (FCurrent = FElementAfterLast);
end;
Note that I can write a custom emulator like below. But I am trying to avoid this and expose the built in one.
你不能.没有类型表示数组的枚举器.当您在数组的元素上编写for..in循环时,编译器通过内联经典的for循环来处理它.
考虑这个程序:
type
TMyEnum = (enum1, enum2, enum3);
var
arr: array [TMyEnum] of Integer;
i: Integer;
begin
for i in arr do
Writeln(i);
Readln;
end.
并生成的代码:
Project1.dpr.13: for i in arr do 004060D7 BE9CAB4000 mov esi,$0040ab9c 004060DC 33DB xor ebx,ebx 004060DE 8B3C9E mov edi,[esi+ebx*4] Project1.dpr.14: Writeln(i); 004060E1 A110784000 mov eax,[$00407810] 004060E6 8BD7 mov edx,edi 004060E8 E823DCFFFF call @Write0Long 004060ED E8FEDEFFFF call @WriteLn 004060F2 E869CCFFFF call @_IOTest 004060F7 43 inc ebx Project1.dpr.13: for i in arr do 004060F8 83FB03 cmp ebx,$03 004060FB 75E1 jnz $004060de Project1.dpr.15: Readln; 004060FD A114784000 mov eax,[$00407814] 00406102 E8E5D7FFFF call @ReadLn 00406107 E854CCFFFF call @_IOTest
坦率地说,你能做的最好的就是你已经拥有的.您已经拥有的问题是堆分配.使用记录而不是类来编写枚举器,如下所示:
type
TArrayEnumerator<T> = record
strict private
type
P = ^T;
strict private
FArr: P;
FIndex: Integer;
FCount: Integer;
public
class function Initialize(const Arr: array of T): TArrayEnumerator<T>; static;
function GetCurrent: T;
function MoveNext: Boolean;
property Current: T read GetCurrent;
end;
class function TArrayEnumerator<T>.Initialize(const Arr: array of T): TArrayEnumerator<T>;
begin
Result.FArr := @Arr[low(Arr)];
Result.FIndex := -1;
Result.FCount := Length(Arr);
end;
function TArrayEnumerator<T>.MoveNext: Boolean;
begin
Result := FIndex < FCount-1;
if Result then
inc(FIndex);
end;
function TArrayEnumerator<T>.GetCurrent: T;
var
Ptr: P;
begin
Ptr := FArr;
inc(Ptr, FIndex);
Result := Ptr^;
end;
然后你的GetEnumerator实现如下:
function TMyClass.GetEnumerator: TArrayEnumerator<Integer>; begin Result := TArrayEnumerator<Integer>.Initialize(FItems); end;
