在我的Delphi程序中,我有一个登录表单,它在创建主表单之前显示,但我面临的问题是我想登录检查在主表单中处理,这意味着登录表单将使用要检查并继续的主要表格, 请阅读以下评论:
请阅读以下评论:
procedure LogInButtonClick(Sender: TObject) ;
这是TLoginForm代码(from delphi.about.com):
unit login;
interface
uses
Windows, Messages, SysUtils, Variants, Classes,
Graphics, Controls, Forms, Dialogs, StdCtrls;
type
TLoginForm = class(TForm)
LogInButton: TButton;
pwdLabel: TLabel;
passwordEdit: TEdit;
procedure LogInButtonClick(Sender: TObject) ;
public
class function Execute : boolean;
end;
implementation
{$R *.dfm}
class function TLoginForm.Execute: boolean;
begin
with TLoginForm.Create(nil) do
try
Result := ShowModal = mrOk;
finally
Free;
end;
end;
procedure TLoginForm.LogInButtonClick(Sender: TObject) ;
begin
if passwordEdit.Text = 'delphi' then
{
Here how it's possible to use :
if MainForm.text=passwordEdit.Text then
ModalResult := mrOK
}
ModalResult := mrOK
else
ModalResult := mrAbort;
end;
end.
这是主程序初始化流程:
program PasswordApp;
uses
Forms,
main in 'main.pas' {MainForm},
login in 'login.pas' {LoginForm};
{$R *.res}
begin
if TLoginForm.Execute then
begin
Application.Initialize;
Application.CreateForm(TMainForm, MainForm) ;
Application.Run;
end
else
begin
Application.MessageBox('You are not authorized to use the application. The password is "delphi".', 'Password Protected Delphi application') ;
end;
end.
谢谢
如果您需要首先创建主表单,请先创建它:begin
Application.Initialize;
Application.CreateForm(TMainForm, MainForm);//created, but not shown
if TLoginForm.Execute then//now the login form can refer to the main form
Application.Run//this shows the main form
else
Application.MessageBox('....');
end;
这是你提出的问题的直接和天真的答案.更广泛地思考,我鼓励您将登录测试移出主表单.把它放在任何更高级代码需要使用的地方.您目前正在努力的设计具有不健康的耦合.
