在Clojure 1.2: (defprotocol PP (foo [bar]) (foo [bar baz]))= PP(extend-protocol PP Object (foo [bar] 1) (foo [bar baz] 2))= nil(foo "hello!")= #CompilerException java.lang.IllegalArgumentException: No single method: foo of interface: PP
(defprotocol PP
(foo [bar])
(foo [bar baz]))
=> PP
(extend-protocol PP
Object
(foo [bar] 1)
(foo [bar baz] 2))
=> nil
(foo "hello!")
=> #<CompilerException java.lang.IllegalArgumentException: No single method: foo of interface: PP found for function: foo of protocol: PP
我哪里错了?作为foo函数的单参数版本的结果,我希望看到1,因为“hello!”显然是java.lang.Object的一个实例。
我认为你的协议中的第二个foo是第一个foo。重载超自然与使用略有不同的语法。user> (defprotocol PP
(foo [bar] [bar baz]))
PP
user> (extend-protocol PP
Object
(foo
([bar] 1)
([bar baz] 2)))
nil
user> (foo "foo")
1
user> (foo "foo" "bar")
2
